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3 years ago

Please type your answers, i can't view other peoples images on here.

Mathematics

1 answer:

lianna [129]3 years ago

7 0

Answer:

Step-by-step explanation:

Since f(x) = 4 $x^{2}$ + $x^{4}$ and g(x) = $\sqrt (x^{2}+4)$ ,

(f g) (x) = f( x ) * g( x ) = ( 4 $x^{2}$ + $x^{4}$ ) ( $x^{2}$ +4 )^(1/2)

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Please help me with this

zvonat [6]

Answer:

Hey there!

The answer is 6/7h=4.

This means that 6/7 of his brother's height is four feet, which is Bryce's height.

Let me know if this helps :)

4 0

3 years ago

Verify sin2θ/1+cos2θ =tanθ

Andrej [43]

Answer:

LHS.= Sin 2x /( 1 + cos2x )

We have , sin 2x = 2 sinx•cosx

And. cos2x = 2cos^2 x - 1

i.e . 1+ cosx 2x = 2cos^2x

Putting the above results in the LHSwe get,

Sin2x/ ( 1+ cos2x ) =2 sinx•cosx/2cos^2x

=sinx / cosx

= Tanx

.•. sin2x/(1 + cos2x)= tanx

Step-by-step explanation:

4 0

2 years ago

Find the value of kk for which the constant function x(t)=kx(t)=k is a solution of the differential equation 5t3dxdt+2x−2=05t3dx

uranmaximum [27]

Given the differential equation

$5t^3 \frac{dx}{dt} +2x-2=0$

The solution is as follows:

$5t^3 \frac{dx}{dt} +2x-2=0 \\ \\ \Rightarrow5t^3 \frac{dx}{dt} =2-2x \\ \\ \Rightarrow \frac{5}{2-2x} dx= \frac{1}{t^3} dt \\ \\ \Rightarrow \int {\frac{5}{2-2x} } \, dx = \int {\frac{1}{t^3}} \, dt \\ \\ \Rightarrow- \frac{5}{2} \ln(2-2x)=- \frac{1}{2t^2} +A \\ \\ \Rightarrow\ln(2-2x)= \frac{1}{5t^2} +B\\ \\ \Rightarrow2-2x=Ce^{\frac{1}{5t^2}} \\ \\ \Rightarrow 2x=Ce^{\frac{1}{5t^2}}+2 \\ \\ \Rightarrow x=De^{\frac{1}{5t^2}}+1$

3 0

3 years ago

Which pair of angles are corresponding angles?

Effectus [21]

Corresponding angles are angles that are the same, and occupy the same relative position.

1 and 2: Incorrect - These are supplementary angles

3 and 5: Incorrect - These are same-side interior angles

2 and 6: Correct - These are corresponding angles

4 and 7: Incorrect - These are alternate interior angles

Hope this helps!! :)

7 0

3 years ago

A woman prospecting for successful business travels 16km from a point P to a point Q on a bearing of 065°. She then travels to p

SashulF [63]

Answer:

The distance PR is 21.6 Km

Step-by-step explanation:

Please find the attached document for explanation.

Also, I applied Cosine rule to determine the distance PR, since i have an angle (Q) in between two given sides of the triangle.

8 0

2 years ago