Math answers so i know the answers

SIZIF [17.4K]

Answer:

8

Step-by-step explanation:

In order to find the length and width necessary to find area, we need to look at the chart. By exmaining, we can see that the length is two units from top-to-bottom. We can also see that the width is 4 units from left-to-right. We can now multiply 4 times 2 to get our answer of 8.

5 0

4 years ago

Read 2 more answers

What does m-7 equal?

Orlov [11]

answer

I think the answer is 142

3 0

3 years ago

Personal Finance: Cost of a Car The suggested list price of a new car is $24,000. The dealer’s cost is 85% of list. How much wil

RUDIKE [14]

Answer: $20,700

Step-by-step explanation:

Given that :

List price of car = $24,000

Dealer's cost = 85% of the list price of the car

Dealer acceptance cost = $300 over the cost

Hence, total amount to be paid :

Dealer's cost + dealer's acceptance cost

Dealer's cost = (0.85 * $24,000) = $21,400

Hence, Total cost :

$20,400 + $300 = $20,700

8 0

3 years ago

Suppose that prices of a certain model of new homes are normally distributed with a mean of $150,000. use the 68-95-99.7 rule to

Novosadov [1.4K]

Answer:

We want to find the percentage of values between 147700 and 152300

$P(147700$

And one way to solve this is use a formula called z score in order to find the number of deviations from the mean for the limits given:

$z= \frac{x-\mu}{\sigma}$

And replacing we got:

$z=\frac{147700-150000}{2300}=-1$

$z=\frac{152300-150000}{2300}=1$

So then we are within 1 deviation from the mean so then we can conclude that the percentage of values between $147,700 and $152,300 is 68%

Step-by-step explanation:

We define the random variable representing the prices of a certain model as X and the distirbution for this random variable is given by:

$X \sim N(\mu = 150000, \sigma =2300$

The empirical rule states that within one deviation from the mean we have 68% of the data, within 2 deviations from the mean we have 95% and within 3 deviations 99.7 % of the data.

We want to find the percentage of values between 147700 and 152300

$P(147700$

And one way to solve this is use a formula called z score in order to find the number of deviations from the mean for the limits given:

$z= \frac{x-\mu}{\sigma}$

And replacing we got:

$z=\frac{147700-150000}{2300}=-1$

$z=\frac{152300-150000}{2300}=1$

So then we are within 1 deviation from the mean so then we can conclude that the percentage of values between $147,700 and $152,300 is 68%

7 0

3 years ago

If the area of the rectangle shown is 150 square feet, we can use the equation 2x2 - 5x = 150 to find its dimensions. If the sol

anzhelika [568]

<span>If the area of the rectangle shown is 150 square feet, we can use the equation 2x2 - 5x = 150 to find its dimensions.</span>

8 0

3 years ago