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3 years ago

Can you help me please?

Mathematics

1 answer:

klemol [59]3 years ago

6 0

Answer:

the answer is true

Step-by-step explanation:

the x values don't repeat themselves so therefore it is a function

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Please help, it says NOT the correct way.

ololo11 [35]

Answer:

The first one or the 2nd one, since it says NOT worth half, I would say the first one is the answer.

Step-by-step explanation:

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2 years ago

The diagram shows an equilateral triangle, a square, and one diagonal of the square. what is the value of x

Verizon [17]

Answer:

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Step-by-step explanation:

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2 years ago

Which function has exactly three distinct real zeros?

quester [9]

H(X) = (x - 2)²(x + 4)(x - 1) has 3 zeroes, they are -4,2 and 1

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3 years ago

Need help fast!! Mark brainliest

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3 years ago

3x^2 + 4x = -8<br> solve using quadratic formula

Firdavs [7]

Use the quadratic equation to solve this (image of the quadratic equation is below)

Remember that quadratic functions are set up like so:

$ax^{2} +bx +c = 0$

To make the equation 3x² + 4x = -8 into a quadratic function you must bring -8 to the left side of the equation so it equals zero. To do this add 8 to both sides

3x² + 4x + 8= -8 + 8

3x² + 4x + 8 = 0

That means that in this equation...

a = 3

b = 4

c = 8

^^^Plug these numbers into the quadratic equation and solve (Keep in mind that +/- is ± )

$\frac{-4+/-\sqrt{(4)^{2}-4(3)(8)}}{2(3)}$

$\frac{-4+/-\sqrt{16-96}}{6}$

$\frac{-4+/-\sqrt{-80}}{6}$

^^^There is no real solution to this equation. You must have an imaginary solution

$\frac{-4+/-i\sqrt{80}}{6}$

Simplify

$\frac{-2+/-2i \sqrt{5}}{3}$

Hope this helped!

~Just a girl in love with Shawn Mendes

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3 years ago