The highlighter that is 11 grams has a greater mass
Hello from MrBillDoesMath!
Answer:
1/ 91.4
Discussion:
Evaluate 1/ ( 3x^3 + 5.2y) when x = 3, y = 2.
1/ (3 (3)^3 + 5.2(2)) =
1/ ( 3 * 27 + 10.4) =
1/ ( 81 + 10.4) =
1/ (91.4) =
.0109 (approx)
Thank you,
MrB
Answer: =(x - 1) x (x^2 + x + 1)
The function F(x) have a vertical asymptote at x =0 and x =1.
Given that
The given Function;

We have to determine
At which value the function F(x) has a vertical asymptote.
According to the question
The given Function;

The function is undefined when the denominator becomes 0. Find values of x for which the denominator is 0:
Then,


The value of x is 0 and 1.
Hence, the function F(x) have a vertical asymptote at x =0 and x =1.
To know more about Parabola click the link given below.
brainly.com/question/12868913