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Jet001 [13]
3 years ago
9

A b and c are different questions

Mathematics
2 answers:
GuDViN [60]3 years ago
3 0

Answer:

A.5

B.12

C.42

Step-by-step explanation:

A. 5th time meaning 72-(0.75*5)=68.25

B.72-63=9 9/0.75=12

C.40*0.75=30 72-30=42

stealth61 [152]3 years ago
3 0
5, 12, & 42 are your answers
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There are 5 red balls, 4 blue balls, 6 yellow balls and 10 green balls in a box,
lys-0071 [83]

<h2 /><h2>Here we go ~ </h2>

According to given information there are :

  • 5 red balls

  • 4 blue balls

  • 6 yellow balls

  • 10 green balls

<h3>1. what is the probability that the ball chosen is red ?</h3>

-

\qquad \sf  \dashrightarrow \: p(red) =  \dfrac{total \: red \: balls}{total \: balls}

\qquad \sf  \dashrightarrow \: p(red) =  \dfrac{5}{5 + 4 + 6 + 10}

\qquad \sf  \dashrightarrow \: p(red) =  \dfrac{5}{25}

\qquad \sf  \dashrightarrow \: p(red) =  \dfrac{1}{5}

<h3>2. what is the probability that the ball chosen is blue ?</h3>

\qquad \sf  \dashrightarrow \: p(blue) =  \dfrac{total \: blue \: balls}{total \: balls}

\qquad \sf  \dashrightarrow \: p(blue) =  \dfrac{4}{5 + 4 + 6 + 10}

\qquad \sf  \dashrightarrow \: p(blue) =  \dfrac{4}{25}

<h3>3. what is the probability that the ball chosen is yellow ?</h3>

\qquad \sf  \dashrightarrow \: p(yellow) =  \dfrac{total \: yellow\: balls}{total \: balls}

\qquad \sf  \dashrightarrow \: p(yellow) =  \dfrac{6}{5 + 4 + 6 + 10}

\qquad \sf  \dashrightarrow \: p(yellow) =  \dfrac{6}{25}

<h3>4. what is the probability that the ball chosen is green ?</h3>

\qquad \sf  \dashrightarrow \: p(green) =  \dfrac{total \: green\: balls}{total \: balls}

\qquad \sf  \dashrightarrow \: p(green) =  \dfrac{10}{5 + 4 + 6 + 10}

\qquad \sf  \dashrightarrow \: p(green) =  \dfrac{10}{25}

\qquad \sf  \dashrightarrow \: p(green) =  \dfrac{2}{5}

<h3>5. what is the probability that the ball chosen is not green ?</h3>

\qquad \sf  \dashrightarrow \: p(not \: green) =  \dfrac{total \: non \: green\: balls}{total \: balls}

\qquad \sf  \dashrightarrow \: p(not \: green) =  \dfrac{5 + 4 + 6}{5 + 4 + 6 + 10}

\qquad \sf  \dashrightarrow \: p(not \: green) =  \dfrac{15}{25}

\qquad \sf  \dashrightarrow \: p(not \: green) =  \dfrac{3}{5}

3 0
2 years ago
Find a solution x = x(t) of the equation x′ + 2x = t2 + 4t + 7 in the form of a quadratic function of t, that is, of the form x(
Temka [501]
The particular quadratic solution to the ODE is found as follows:

x=at^2+bt+c
x'=2at+b

(2at+b)+2(at^2+bt+c)=t^2+4t+7
2at^2+(2a+2b)t+(b+2c)=t^2+4t+7

\begin{cases}2a=1\\2(a+b)=4\\b+2c=7\end{cases}\implies a=\dfrac12,b=\dfrac32,c=\dfrac{11}4

Note that there's also the fundamental solution to account for, which is obtained from the characteristic equation for the ODE:

x'+2x=0\implies r+2=0\implies r=-2

so that x_c=Ce^{-2t} is a characteristic solution to the ODE, and the general solution would be

x=Ce^{-2t}+\dfrac{t^2}2+\dfrac{3t}2+\dfrac{11}4
4 0
3 years ago
The chord XY is a diameter of of O. True or false?
steposvetlana [31]

Answer:

False

Step-by-step explanation:

XY is the diameter of the circle with the centre of this circle being O.

But O on it's own is just a coordinate, and not the circle.

3 0
3 years ago
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Match each binomial expression with the set of coefficients of the terms obtained by expanding the expression.
user100 [1]

 explanation:

(A) (2x+y)^3=8 x^3 + 12 x^2 y + 6 x y^2 + y^3

Answer option C)  8, 12, 6, 1

B) (2x+3y)^4 = 16 x^4 + 96 x^3 y + 216 x^2 y^2 + 216 x y^3 + 81 y^4

Answer option D) 16, 96, 216, 216, 81

C) (3x+2y)^3 = 27 x^3 + 54 x^2 y + 36 x y^2 + 8 y^3

Answer option B) 27, 54, 36, 8

D)(x+y)^4 = x^4 + 4 x^3 y + 6 x^2 y^2 + 4 x y^3 + y^4

Answer option A) 1, 4, 6, 4, 1

8 0
3 years ago
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The formula for distance is given as distance = speed x time. Use the formula to find:
goldenfox [79]
You just put the numbers in the formula 3x30 = 90 km
3 0
2 years ago
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