The formula for the perimeter of a rectangle is 2(1 + w), where
2 answers:
Answer:
<h2><em>5</em><em>0</em><em> </em><em>ft</em></h2><em>Solution,</em>
<em>Length=</em><em>1</em><em>7</em><em> </em><em>ft</em>
<em>Width=</em><em>8</em><em> </em><em>ft</em>
<em>Now,</em>
<em></em>
<em>hope </em><em>this </em><em>helps.</em><em>.</em><em>.</em><em>.</em>
<em>Good </em><em>luck</em><em> on</em><em> </em><em>your </em><em>assignment</em><em>.</em><em>.</em><em>.</em>
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If a quadrilateral is a rhombus then:
i) all its sides have equal length,
and
ii) the 2 diagonals are perpendicular and bisect each other.
The 2 diagonals of rhombus JKLM intersect at N.
Then m(MNJ)=90°, |JN|=4 and |NM|=3 units
thus, by the Pythagorean theorem,
The perimeter of the rhombus is 4*5 units=20 units.
Answer: 20 units
i) all its sides have equal length,
and
ii) the 2 diagonals are perpendicular and bisect each other.
The 2 diagonals of rhombus JKLM intersect at N.
Then m(MNJ)=90°, |JN|=4 and |NM|=3 units
thus, by the Pythagorean theorem,
The perimeter of the rhombus is 4*5 units=20 units.
Answer: 20 units