We have that
points A (-5, 6) and B (7, -1)

Part A)
find the distance
d=√[(y2-y1)²+(x2-x1)²]-------> d=√[(-1-6)²+(7+5)²]----> d=√(49+144)
d=√193 units

Part B)
find the midpoint
ABx=(x1+x2)/2-----> (-5+7)/2-----> ABx=1
ABy=(y1+y2)/2-----> (-1+6)/2-----> ABy=2.5

the midpoint is (1,2.5)

Part C)
find the slope
m=(y2-y1)/(x2-x1)-----> m=(-1-6)/(7+5)--------> m=-7/12

the slope m=-7/12

4 0

4 years ago

Consider the line y = x – 4.

FrozenT [24]

Answer:

A line parallel to the line y = x -4 would have a slope of 1.

A line perpendicular to the line y = x -4 would have a slope of -1.

Remember, parallel lines are lines that never intersect, which means that they cannot possibly have different slopes. A perpendicular line will always have the opposite slope as the first line, because the two lines must intersect at a 90 degree angle. The attached image shows how this works.

Hope this helps you out!