All categories

3 years ago

A card is selected at random from a standard deck of 52 cards find the probability of choosing a spade or a 8card

Mathematics

1 answer:

Nina [5.8K]3 years ago

4 0

Answer: 8 out of 52

Step-by-step explanation: there are 52 cards and you are trying to figure out out 52 which one out the 52 would be 8 or a spade there are 4 8 cards and 4 spade cards the answer would be 8 out of 52 Hope this Helps You!

You might be interested in

Which complex number has an absolute value of 5?<br> someon explain

harkovskaia [24]

The absolute value of -5 is 5, and the absolute value of 5 is also 5. ∣ a + b i ∣ = a 2 + b 2 . |a+bi| = \sqrt{a^2 +b^2}.

6 0

4 years ago

I need help is it A B C or D

Reptile [31]

The question is asking you to solve for A

to determine the first, fourth and tenth term you simply put those values in for (n)

the first term you then be given by the equation A(1) = 12 + ((1)-1)(3)

A= 12

Same thing for 4th term A(4) = 12 + ((4)-1)(3)

A= 21

10th term: A(10) = 12 + ((10)-1)(3)

A= 39

∴ your answer is C

4 0

4 years ago

Twenty-four girls are trying out for 12 spots on the cheerleading team. If you wanted to determine how many different groups of

Tju [1.3M]

Combination I believe

Hope this helps

6 0

4 years ago

Read 2 more answers

A 98% confidence interval for the mean of a population is to be constructed and must be accurate to within 0.3 unit. A prelimina

BaLLatris [955]

Answer:

$n = (\frac{2.326*1.7}{0.3})^2= 173.73$

And the value for n rounded up would be n = 174

Step-by-step explanation:

We have the following info given:

$s= 1.7$ previous estimation for the deviation

$ME=0.03$ the margin of error desired

$Conf =0.98$ represent the confidence

The Margin of error is given by:

$ME = z_{\alpha/2} \frac{\sigma}{\sqrt{n}}$

If we solve for the value of n we got:

$n= (\frac{z*\sigma}{ME})^2$

For this problem we know that the confidence is 98% so then the significance level would be $\alpha=0.02$ and the critical value would be:

$z_{\alpha/2}= 2.326$

And replacing we got:

$n = (\frac{2.326*1.7}{0.3})^2= 173.73$

And the value for n rounded up would be n = 174

3 0

3 years ago

. 7 prizes are to be distributed between 3 people with a guarantee that each person gets at least one prize. Find the number of

ANEK [815]

Answer:

Total number of ways to distribute the prize = 2187

$3^{7}= 2187$

Step-by-step explanation:

Given:

Number of prizes = 7

Number of peoples = 3

We need to find the total number of ways to distribute the prize.

Solution:

From the above statement, 7 prizes are to be distributed between 3 people, wherein each person gets at least one prize.

Each prize is to be distributed among three persons. When the first prize is to be awarded, one of the three is chosen to win the prize. When the second prize is to be awarded, there are again three choices.

So, total number of distribution of the prizes is given as:

$3\times 3 \times 3\times 3\times 3\times 3\times 3=3^{7}$

$3^{7}= 2187$

Therefore, total number of ways to distribute the prizes = 2187

7 0

3 years ago