3(√x+1-5)=27
divide both sides by 3
√x+1-5= 27
add 5 to both sides
√x+1=27+5
√x+1=32
take square of both sides
x+1=32
subtract 1 from each sides
x=32-1
x=31
Answer:
63.5
Step-by-step explanation:
Answer:
6 mins
Step-by-step explanation:
Given that;
T(t) = Ce^-kt + T(s)
Since T(t) = 200◦F, and T(s) = 70◦F where t = 0
200= Ce^-k(0) + 70
C= 200 - 70
C = 130
Then when T(t) = 190◦F and t= 1s ;
190 = 130e^-(k *1) + 70
190 - 70 = 130e-^(k *1)
120/130 = e^k
0.923 = e^-k
-k = ln(0.923)
k = 0.08
To determine the time taken to reach a temperature of 150◦F
150 = 130e^-(0.08t) + 70
150 - 70/130 = e^-(0.08t)
0.6154 = e^-(0.08t)
-(0.08t) = ln 0.6154
0.08t = 0.4855
t = 0.4855/0.08
t = 6 mins
Answer:
1/4
Step-by-step explanation:
the equation for slope is (y2 - y1) / (x2 - x1)
so the equation is (4-8)/(3-19)
= -4/-16
= 4/16
= 1/4, therefore, the slope is 1/4 or 0.25 as a decimal
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