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Natasha_Volkova [10]

4 years ago

8

Evaluate d – (–3.5) when d = 2.74.

1 answer:

Allushta [10]4 years ago

7 0

$d-(-3.5) \ when \\ d=2.74
2.74-(-3.5) \\
=2.74-(-3.5) \\
=2.74+3.5 \\
=6.24 \\$

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what is the standard deviation and variance of 10, 10, 10, 10, 13, 20, 23, 32, 32, 32, 32, 47, 50, 53, 60, 60, 63, 72, 72, 72, 7

Archy [21]

Answer:

bro/sis through this solution u can solve ur values

Step-by-step explanation:

To calculate the variance, you first subtract the mean from each number and then square the results to find the squared differences. You then find the average of those squared differences. The result is the variance. The standard deviation is a measure of how spread out the numbers in a distribution are.

I hope this will help you

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3 years ago

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DedPeter [7]

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8 0

3 years ago

Read 2 more answers

Evaluate the expression when =y−7.<br> y^2+4y-5

Sophie [7]

(-7)^2 + 4(-7) -5
= 49 - 28 -5
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5 0

3 years ago

Will someone please help me here

motikmotik

Both pictures have a right triangle. Its hypotenuse = 5,

so D=5.

a longer leg C=4,

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5 0

3 years ago

What are the central angles of the sectors representing nuclear energy in both the years?( you may round the numbers before find

xeze [42]

Answer:

1995 => 22°

2005 => 36°

Step-by-step explanation:

Central angle of the sector representing nuclear energy in 1995 = percentage of nuclear energy in 1995 ÷ 100 × 360°

Nuclear energy is approximately 6% (rounded to whole number) in 1995.

Central angle = $\frac{6}{100}*360 = \frac{6}{10}*36$

$= \frac{216}{10} = 21.6$

Central angle representing nuclear energy in 1995 ≈ 22° (nearest whole number).

Central angle of the sector representing nuclear energy in 2005 = percentage of nuclear energy in 2005 ÷ 100 × 360°

Nuclear energy is approximately 10% (rounded to whole number) in 1995.

Central angle = $\frac{10}{100}*360 = \frac{1}{1}*36$

$= \frac{36} = 36$

Central angle representing nuclear energy in 2005 = 36°.

7 0

3 years ago