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Sedbober [7]
3 years ago
6

In an imaginary economy, consumers buy only sandwiches and magazines. The fixed basket consists of 20 sandwiches and 30 magazine

s. In 2006, a sandwich cost $4 and a magazine cost $2. In 2007, a sandwich cost $5. The base year is 2006. If the consumer price index in 2007 was 125, then how much did a magazine cost in 2007?
a. $1.87
b. $2.08
c. $2.32
d. $3.00
Business
1 answer:
rodikova [14]3 years ago
4 0

Answer:

$2.5

Explanation:

Given:

Number of sandwiches in basket = 20

Number of magazines in basket = 30

cost of sandwiches in 2006 = $4

Cost of magazines in 2006 = $2

cost of sandwiches in 2007 = $5

Consumer price index in 2007 = 125

Now,

Consumer price index = \frac{\sum(p_1q0)}{\sum(p_0q0)}\times100

or

125 = \frac{20\times\$5+30\times X}{20\times\$4+30\times\$2}\times100

here,

X is the price of magazines in 2007

thus,

125 = \frac{\$100+30\times X}{$80+$60}\times100

or

1.25 × ($80 + $60 ) = $100 + 30X

or

30X = $175 - $100

or

X = $2.5

Hence,

The price of magazines in 2007 was $2.5

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There are a number goods that over time, for a variety of reasons, transition from being a normal good to an inferior good or fr
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Answer:

d. the camry becomes an inferior good because the good is now perceived as lower in quality than a lexus

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How could this happen?

<u>This could only have happened because of a change in perception in households over time. </u>

It is stated in the Scenario that ''today more Toyota Camrys are purchased by households that have experienced a reduction in income.''

<u>That means Toyota Camry has become an inferior good that is purchased more when income falls.</u>

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7 0
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______ indicators can be traced after the product has been launched to view if it meets product goals and user requirements.
Keith_Richards [23]

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Explanation:

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6 0
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Sove 3logx + 5 is equal to 8​
e-lub [12.9K]

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

3 log(x)  + 5 = 8

Subtract sides 5

3  log(x)  + 5 - 5 = 8 - 5

3 log(x)  = 3

Divide sides by 3

\frac{3 log(x) }{3}  =  \frac{3}{ 3}  \\

log(x)  = 1

_________________________________

<em>Remi</em><em>nder</em><em> </em><em>:</em><em> </em>

log_{a}(x)  = b

x =  {a}^{b}

_________________________________

Thus ;

log_{10}(x)  = 1

x =  {10}^{1}

x = 10

Done...

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

8 0
3 years ago
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