Question

POINTS! + WHOEVER ANSWERS BOTH CORRECTLY GETS TO BE THE BRAIN!!!!!!!!

Answer 1

Answer:

Part A. $57x^5 \text{divided by} 19x^2=3x^3$

Party B. Excluded value 19

Step-by-step explanation:

Given : $57x^5 \text{divided by} 19x^2$

Part A. Simplify the algebraic fraction.

Step 1- Write the expression

$57x^5 \text{divided by} 19x^2=\frac{57x^5}{19x^2}$

Step 2- In division same base powers get subtracted

$=\frac{57x^{5-2}}{19}$

$=\frac{57x^{3}}{19}$

Step 3- Divide 57 by 19

$=3x^{3}$

Therefore, $57x^5 \text{divided by} 19x^2=3x^3$

Part B.  Determine the excluded value(s) of the variable. In two or more complete sentence, explain how you determine the excluded value and why it cannot be possible value for the variable.

Excluded value of the variable is 19

because, 19 comes on both the side as the factor of 57 is 19×3

So we can write 57 in the form of  19×3 and by divisor of 19 it cancel out.

So, automatically 19 has to be cancel out in any situation you can also see in above steps.

Therefore, it cannot be possible value for the variable.

Answer 2

(3•19x5) Simplify ———————— 19x2 Dividing exponential expressions :

 3.1    x5 divided by x2 = x(5 - 2) = x3

Canceling Out :

 3.2      Canceling out  19  as it appears on both sides of the fraction line 

Final result : 3x3