Radius, r = 3
The equation of a sphere entered at the origin in cartesian coordinates is
x^2 + y^2 + z^2 = r^2
That in spherical coordinates is:
x = rcos(theta)*sin(phi)
y= r sin(theta)*sin(phi)
z = rcos(phi)
where you can make u = r cos(phi) to obtain the parametrical equations
x = √[r^2 - u^2] cos(theta)
y = √[r^2 - u^2] sin (theta)
z = u
where theta goes from 0 to 2π and u goes from -r to r.
In our case r = 3, so the parametrical equations are:
Answer:
x = √[9 - u^2] cos(theta)
y = √[9 - u^2] sin (theta)
z = u
Answer:
B. x<27
Step-by-step explanation:
300-165=135
135/5=27
Answer:The area is 14306. 625 cm.
Step-by-step explanation:
To find the area of the circle, we will need to find the diameter and find the radius.
So we know the circumference is 423.9 m and we know to get the circumference, you will need to multiply pie by the diameter .
so now we need divide the circumference by pie to find the diameter.
423.9/ 3.14 = 135 so 135 is the diameter.
To find the radius we need to divide the diameter by 2.
135/2 = 67.5
Now is time to find the area which uses the formula A= nr^2
A = 3.14 * 67.5^2
A = 14306. 625
Answer: If you are suppose to write an algebraic expression it is: 5 - 2x = 3x - 5
If you are suppose to solve the answer is:
5-2x=3x-5
-2x=3x-10
-5x=-10
x=2
