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Paul [167]
3 years ago
12

Help me with 13,14,15 !!

Mathematics
1 answer:
a_sh-v [17]3 years ago
3 0
Get a calucalotor for the answers

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Which of the following ordered pairs should be tested to determine which side to shade when graphing the inequality
Veseljchak [2.6K]

Answer:

A

Step-by-step explanation:

Pick any point on any side of the line. substitute X and Y in the inequality for (x,y)-the point you chose. If you simplify and the inequality is true, shade in that side. If it is false, shade in the other side.

5 0
3 years ago
Read 2 more answers
George filled 10 mugs with coffee. Each mug had 240\text{ mL}240 mL240, start text, space, m, L, end text of coffee. How many li
goldenfox [79]

Answer:

2.4 Liters

Step-by-step explanation:

1,000

1

​

 L1, start text, space, m, L, end text, equals, start fraction, 1, divided by, 1, comma, 000, end fraction, start text, space, L, end text

So, 2,400 mL

​

 

=2,400 mL×

1,000 mL

1 L

​

=

1

2,400

mL

​

×

1,000

mL

1 L

​

=

1,000

2,400 L

​

=2,400 L÷1,000

=2.4 L

​

4 0
3 years ago
Read 2 more answers
I need help please and thank you​
Andrej [43]

Answer:

a=-7.275*967

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Pls help me on this question
astraxan [27]

Answer:

h < 2

Step-by-step explanation:

Step 1: Distribute

10h + 40 < 60

Step 2: Subtract 40 on both sides

10h < 20

Step 3: Divide both sides by 10

h < 2

4 0
3 years ago
The population of a city has been increasing by 2% annually. In 2000, the population was 315,000. Predict the population of the
Minchanka [31]

Answer:

The population of the city in 2020 is 3,839,832

Step-by-step explanation:

Given:

Population at 2000 =  315,000

Rate at which the population increases = 2%

To Find:

The Population in the city after 2020 = ?

Solution:

The population in the city after 2020 can be found by using Exponential growth function.

Exponential growth occurs when a quantity increases by the same factor

Exponential growth function is y = a(1 + r)^t

Where

y is the final amount

a is the initial amount

r is the rate of  increase

t is the time period.

Now substituting the values ,

In 2020 i.e., after 10 years

y = 315000(1 + 2 \%)^{10}

y = 315000(1 + \frac{2}{100})^{10}

y = 315000(1 + 0.02)^{10}

y = 315000(1.02)^{10}

y = 315000\times 1.218

y = 3,839,832.42

4 0
3 years ago
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