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3 years ago

Ann bought 4 cameras and 2 computers for $2868.32

Mathematics

1 answer:

Katyanochek1 [597]3 years ago

7 0

Answer:

$532.03

Step-by-step explanation:

Ann: 4 cameras + 2 computers = $2868.32

Sister: 2 cameras + 5 computers = $3562.28

If the sister has bought 2 sets:

Sister: 4 cameras + 10 computers = 3562.28 x 2 = $7124.56

Comparing the two equations:

4 cameras + 2 computers = $2868.32

4 cameras + 10 computers = $7124.56

We can conclude that:

10 - 2 computers = 7124.56 - 2868.32

8 computers = $4256.24

If 8 computers = $4256.24

1 computer = $4256.24 ÷ 8 = $532.03

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