Answer:
The angle formed between CF and the plane ABCD is approximately 47.14°
Step-by-step explanation:
The given parameters are;
BC = 6.8
DE = 9.3
∠BAC = 52°
We note that the angles formed by the vertex of a cuboid are right triangles, therefore, by trigonometric ratios, we get;
sin∠BAC = BC/(The length of a line drawn from A to C)
∴ The length of the line drawn from A to C = BC/sin∠BAC
The length of the line drawn from A to C = 6.8/sin(52°) ≈ 8.63
∴ AC = 8.63
By trigonometry, we have;
The angle formed between CF and the plane ABCD = Angle ∠ACF
In a cuboid, FA = BG = CH = DE = 9.3
The angle formed between CF and the plane ABCD = Angle ∠ACF ≈ 47.14°
We will set each parentheses equal to 0
x - 4 = 0
x = 4
-5x + 1 = 0
x = 1/5
The lesser value will be 1/5
The greater value will be 4
Answer:x=1.5
Step-by-step explanation:
Given
Two points co-ordinates are given
A=(5,-8)
B=(5,4)
let other point be C =(x,y)
Area of triangle is given by
A=20-5y+40-8x+5y-4x
A=60-8x
and A=48 square unit
48=60-8x
x=1.5
As area is independent of y therefore at x=1.5 any value of y will give area of 48 square unit
I think it's cost price
I heard it before somewhere
Hope I've been any help to you
Midpoint = (x1+x2)/2 and (y1+y2)/2 = so just solving for
x gives (4+(-2))/2 = 1
not asked for but the y value is (3+6)/2 = 9/2 = 4.5 so the ordered pair is (1, 4.5)
