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1 year ago

Help me with this problem

Mathematics

1 answer:

slega [8]1 year ago

4 0

Answer:

$20x^3-14x^2+37x-7$

Explanation: We need to simplify the given expression:

$(4x^2-2x+7)(5x-1)$

Simplification step by step:

$4x^2(5x-1)-2x(5x-1)+7(5x-1)$ $4x^2\times5x-4x^2-2x\times5x+2x+7\times5x-7$ $20x^3-4x^2-10x^2+2x+35x-7=20x^3-14x^2+37x-7$

Therefore this is the simplified expression:

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Tonya and Pearl each completed a separate proof to show that alternate interior angles AKL and FLK are congruent. Who completed

zalisa [80]

Answer:

Tonya proof is correct
and Pearl proof is wrong

Step-by-step explanation:

AKL and GKB are obviously congruent. But the reasons given are different, One of the justification is Vertical Angles Theorem, and the other is Adjacent Angles.

But the correct justification is the Vertical Angles Theorem, because the angles are Vertically away from each other, or the angles are at opposite sides of each other. Which is when Vertical Angles Theorem is applied.
Making Tonya correct since that was the answer he given.

The definition of Adjacent Angles is incorrect, this Theorem is used when the angles are Adjacent to each other. When the angles are on the same line as the other angle, is when the definition of Adjacent Angles is applied. Not in this situation

8 0

2 years ago

Josh bought a pizza with eight slices of pizza for $12. What is the cost of a slice of pizza? $12 $3 $1 $1.50

rewona [7]

Answer:

$1.50

Step-by-step explanation:

12÷8=3/2 or 1.50

5 0

4 years ago

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Find the solution of the differential equation that satisfies the given initial condition. y' tan x = 3a + y, y(π/3) = 3a, 0 &lt

Paladinen [302]

Answer:

$y(x)=4a\sqrt{3}* sin(x)-3a$

Step-by-step explanation:

We have a separable equation, first let's rewrite the equation as:

$\frac{dy(x)}{dx} =\frac{3a+y}{tan(x)}$

But:

$\frac{1}{tan(x)} =cot(x)$

So:

$\frac{dy(x)}{dx} =cot(x)*(3a+y)$

Multiplying both sides by dx and dividing both sides by 3a+y:

$\frac{dy}{3a+y} =cot(x)dx$

Integrating both sides:

$\int\ \frac{dy}{3a+y} =\int\cot(x) \, dx$

Evaluating the integrals:

$log(3a+y)=log(sin(x))+C_1$

Where C1 is an arbitrary constant.

Solving for y:

$y(x)=-3a+e^{C_1} sin(x)$

$e^{C_1} =constant$

So:

$y(x)=C_1*sin(x)-3a$

Finally, let's evaluate the initial condition in order to find C1:

$y(\frac{\pi}{3} )=3a=C_1*sin(\frac{\pi}{3})-3a\\ 3a=C_1*\frac{\sqrt{3} }{2} -3a$

Solving for C1:

$C_1=4a\sqrt{3}$

Therefore:

$y(x)=4a\sqrt{3}* sin(x)-3a$

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4 years ago

ANSWER ASAP DONT SEND A FILE WHAT IS THE TRANSFORMATION????

mina [271]

Answer:

Hi, I believe this is reflection then rotation. I haven't studied this in some time but from what I remember I think that would be the right answer. I hope I helped, have a nice day :)

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3 years ago

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7.5% sales tax on a $210.00 pendant

KonstantinChe [14]

Answer:

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Step-by-step explanation:

Before Tax Price: $210.00

Sale Tax: 7.50% or $15.75

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3 years ago

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