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3 years ago

I need help on this quiz.Its due tomorrow please help.

Mathematics

1 answer:

sineoko [7]3 years ago

7 0

IS Y=2x^2 or Y=2X^3
give me the exponent

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Find the volume of a frustum of a right pyramid whose lower base is a square with a side 5in. And whose upper base is a square w

mina [271]

The volume of the frustrum is the difference in the volumes of these two pyramids:
30 * 5^2 / 3 - 18 * 3^2 / 3 
= 750/3 - 162/3 
= 250 - 54 
= 196 cubic inches.

You're Answer is A- 196 cu in.

3 0

3 years ago

The formula for electrical power is P, is P= I^2 R, where I is current and R is resistance. The formula for I in terms of. P and

Butoxors [25]

Ans

I = sqrt(P/R)

Step-by-step explanation:

You divide both sides by R first

P/R = I^2 R/R

So,

I^2 = P/R

take the square root of both sides

I = sqrt(P/R)

7 0

3 years ago

Read 2 more answers

Please help me......

LenKa [72]

Answer:

C. m ≥ 9

Step-by-step explanation:

7m -2 ≥ 61

7m ≥ 61+2

7m ≥ 63

m ≥ 63/7

m ≥ 9

7 0

3 years ago

What is the degree AND direction of rotation that takes ΔQRS to ΔQ'R'S'?

ddd [48]

The degree and direction of rotation that takes ΔQRS to ΔQ'R'S' is:

45 degrees; anticlockwise direction.

<h3>What is rotation in math?</h3>

The transformation by rotation refers to the movement of a shape or point in a circular path about a fixed point.

When the shape moves in an anticlockwise direction, it means that It is going in the opposite way as the hands of a clock do.

Learn more about rotation in math:
brainly.com/question/26249005
#SPJ1

7 0

1 year ago

Find the approximate area between the curve f(x) = -4x² + 32x and on the x-axis on the interval [0,8] using 4 rectangles. Use th

Doss [256]

Split up the interval [0, 8] into 4 equally spaced subintervals:

[0, 2], [2, 4], [4, 6], [6, 8]

Take the right endpoints, which form the arithmetic sequence

$r_i=2+\dfrac{8-0}4(i-1)=2i$

where 1 ≤ i ≤ 4.

Find the values of the function at these endpoints:

$f(r_i)=-4{r_i}^2+32r_i=-16i^2+64i$

The area is given approximately by the Riemann sum,

$\displaystyle\int_0^8f(x)\,\mathrm dx\approx\sum_{i=1}^4f(r_i)\Delta x_i$

where $\Delta x_i=\frac{8-0}4=2$ ; so the area is approximately

$\displaystyle2\sum_{i=1}^4(-16i^2+64i)=-32\sum_{i=1}^4i^2+128\sum_{i=1}^4i=-32\cdot\frac{4\cdot5\cdot9}6+128\cdot\frac{4\cdot5}2=\boxed{320}$

where we use the formulas,

$\displaystyle\sum_{i=1}^ni=\frac{n(n+1)}2$

$\displaystyle\sum_{i=1}^ni^2=\frac{n(n+1)(2n+1)}6$

6 0

3 years ago