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If <em>a</em> is fixed and <em>b</em>,<em>c</em> are unknowns then the equation <em>b</em>+<em>c</em>=10-<em>a</em> has 11-<em>a</em> solutions. They are pairs (b,c): (0,10-a), (1,9-a), (2,8-a), ... (10-a,0). As <em>a</em> runs from 0 to 10 we have total number of solutions (11-0)+(11-1)+...(11-1)=11+10+...+1=(1+11)*11/2=66.
let's firstly convert the mixed fractions to improper fractions and then divide.
![\bf \stackrel{mixed}{17\frac{13}{18}}\implies \cfrac{17\cdot 18 +13}{18}\implies \stackrel{improper}{\cfrac{319}{18}}~\hfill \stackrel{mixed}{2\frac{7}{9}}\implies \cfrac{2\cdot 9+7}{9}\implies \stackrel{improper}{\cfrac{25}{9}} \\\\[-0.35em] ~\dotfill](https://tex.z-dn.net/?f=%5Cbf%20%5Cstackrel%7Bmixed%7D%7B17%5Cfrac%7B13%7D%7B18%7D%7D%5Cimplies%20%5Ccfrac%7B17%5Ccdot%2018%20%2B13%7D%7B18%7D%5Cimplies%20%5Cstackrel%7Bimproper%7D%7B%5Ccfrac%7B319%7D%7B18%7D%7D~%5Chfill%20%5Cstackrel%7Bmixed%7D%7B2%5Cfrac%7B7%7D%7B9%7D%7D%5Cimplies%20%5Ccfrac%7B2%5Ccdot%209%2B7%7D%7B9%7D%5Cimplies%20%5Cstackrel%7Bimproper%7D%7B%5Ccfrac%7B25%7D%7B9%7D%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill)
![\bf \cfrac{319}{18}\div \cfrac{25}{9}\implies \cfrac{319}{\underset{2}{~~\begin{matrix} 18 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}}\cdot \cfrac{\stackrel{1}{~~\begin{matrix} 9 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}}{25}\implies \cfrac{319}{50}\implies 6\frac{19}{50}](https://tex.z-dn.net/?f=%5Cbf%20%5Ccfrac%7B319%7D%7B18%7D%5Cdiv%20%5Ccfrac%7B25%7D%7B9%7D%5Cimplies%20%5Ccfrac%7B319%7D%7B%5Cunderset%7B2%7D%7B~~%5Cbegin%7Bmatrix%7D%2018%20%5C%5C%5B-0.7em%5D%5Ccline%7B1-1%7D%5C%5C%5B-5pt%5D%5Cend%7Bmatrix%7D~~%7D%7D%5Ccdot%20%5Ccfrac%7B%5Cstackrel%7B1%7D%7B~~%5Cbegin%7Bmatrix%7D%209%20%5C%5C%5B-0.7em%5D%5Ccline%7B1-1%7D%5C%5C%5B-5pt%5D%5Cend%7Bmatrix%7D~~%7D%7D%7B25%7D%5Cimplies%20%5Ccfrac%7B319%7D%7B50%7D%5Cimplies%206%5Cfrac%7B19%7D%7B50%7D)
Answer:
-480
Step-by-step explanation:
If f varies directly as g, and inversely as h, then we can write the variation equation:
, where k is the constant of variation.
If g=56 when h=-2 and f=-7, then we substitute these values into the formula to find the value of k.
The equation now becomes:
if f=10 and h=-12, then;
The correct answer is B.
M^3 + 9m =
There is a common factor of m.
= m(m^2 + 9)
That is the complete factorization.
m^2 + 9 is a sum of two squares which is not factorable.
Answer: m(m^2 + 9)
