Answer:
- h = 0 when the ball hits the ground
- about 3.464 seconds
Step-by-step explanation:
The formula gives h = 192 when t=0, so we assume that h represents the height above the ground. The ball will have a height of 0 when it hits the ground.
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Using that in the equation, we can solve for t.
0 = 192 -16t^2
0 = 12 -t^2 . . . . . . divide by 16
t^2 = 12 . . . . . . . . add t^2
t = √12 = 2√3 ≈ 3.464 . . . . take the square root
It will take 2√3 seconds, about 3.464 seconds, for the ball to hit the ground.
Answer:
10
Step-by-step explanation:
The question is wrong it should be 5C3
5C3=5!/((5-3)!•3!)=5!/(2!•3!)
=(5•4•3•2•1)/(2•1•3•2•1)
=10
2 - 101
3 - 101
4 - 79
5 - 79
6 - 101
lol hope this helps <33
Answer:
c
Step-by-step explanation:
First you subtract 25 from 5 which equals 20 then you multipliy 4 to 20 and you get 80...so 80 is your solution.
