Question

An experiment consists of tossing 3 coins at the same time. What is the probability of tossing 2 tails and 1 head?

Answer 1

Answer:

3/8 or 0.375 or 37.5%

Step-by-step explanation:

You have three coins. The probability of getting a head or a tail for each coin is 1/2. So,

$\frac{1}{2}$ × $\frac{1}{2}$ × $\frac{1}{2}$ = $\frac{1}{8}$

There are 8 possible combinations that can come from tossing 3 coins at the same time: HHH, HHT, HTH, HTT, THH, THT , TTH , or TTT.

Every time you toss the 3 coins, there is a $\frac{1}{8}$ chance that you get either of these combinations. So,

$\frac{1}{8}$ + $\frac{1}{8}$ + $\frac{1}{8}$ = $\frac{3}{8}$

The probability of tossing 2 tails and 1 head is 3/8.

Hope this helps.

Answer 2

Answer:

3/8.

Step-by-step explanation:

The probability of a head or a tail on one toss of a single coin is 1/2.

So the required probability when 3 coins are tossed of getting say 3 heads  = (1/2)*3 = 1/8.

The probabilities are multiplied because each event ( 1 coin tossed) is independent of the others.

There are  3 ways to get 2 H and 1 tail  (HHT, HTH and THH) so the answer is  3 * 1/8

= 3/8.