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Murljashka [212]

2 years ago

12

Jerry pick 16 apples he picked 27 green apples how many apples did Jerry pick label the bar model write a number sentence with a

square for the missing number solve

1 answer:

Katena32 [7]2 years ago

5 0

I'm not for sure but I think 43 sorry if I get it wrong

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Every day in gym class, the fourth graders warm up and play a game. Today, the class warmed up for 8 minutes. Then, they played

mr Goodwill [35]

The game was 6 times as long as the warmup.

3 0

11 months ago

Based on the abbreviations, translate the following ads into fully spelled-out sentences. The final sentence should state how ma

frozen [14]

Answer:

Step-by-step explanation:

Given are the phrases which are to be decoded

3 Br, 1 frplc, pool, upgraded crpt, custom drpes

The context is for sale of house/flat near a grade school

Hence in this context we can find this codes pertain to real estatebusiness.

3 Br = three or triple bed room

1 frpic = One fireplace

Pool = swimming pool

Upgraded crpt = upgraded carpet

custom drpes = custom drapes

7 0

3 years ago

Read 2 more answers

Choose the required figure.

zloy xaker [14]

not sure how the first two pictures apply here, since they're just a single circle.

check the picture below.

the one on the left can have 3 common tangent lines, the one on the right, only two common ones.

5 0

3 years ago

Without using a calculator convert the decimal into a fraction<br> 0. 75

mojhsa [17]

Step-by-step explanation:

Decimals can always be put over 1, as they're part of a whole number.

$\frac{0.75}{1}$

<u>Multiply both numerator and denominator by 100:</u>

<u /> $\frac{0.75 \times 100}{1\times 100} =\frac{75}{100}$

$\frac{0.75}{1} \: and \: \frac{75}{100} \: are \: fractions \: of \: 0.75$

3 0

2 years ago

Use the definition of the derivative to differentiate v=4/2 pie r^3

nata0808 [166]

I suspect 4/2 should actually be 4/3, since 4/2 = 2, while 4/3 would make V the volume of a sphere with radius r. But I'll stick with what's given:

$\displaystyle \frac{dV}{dr} = \lim_{h\to0} \frac{2\pi(r+h)^3-2\pi r^3}{h}$

$\displaystyle \frac{dV}{dr} = 2\pi \lim_{h\to0} \frac{(r^3+3r^2h+3rh^2+h^3)- r^3}{h}$

$\displaystyle \frac{dV}{dr} = 2\pi \lim_{h\to0} \frac{3r^2h+3rh^2+h^3}{h}$

$\displaystyle \frac{dV}{dr} = 2\pi \lim_{h\to0} (3r^2+3rh+h^2)$

$\displaystyle \frac{dV}{dr} = 2\pi \cdot 3r^2 = \boxed{6\pi r^2}$

In Mathematica, you can check this result via

D[4/2*Pi*r^3, r]

3 0

2 years ago