In this case, we cannot simply take the average speed by
adding the two speeds and divide by two.
What we have to do is to calculate the time required
going to school and the return trip home.
We know that to calculate time, we use the formula:
t = d / v
where,
d = distance = 4.8 km = 4800 m
v = velocity
Let us say that the variables related to the trip going
to school is associated with 1, and the return trip home is 2. So,
t1 = 4800 m / (22.6 m / s)
t1 = 212.39 s
t2 = 4800 / (16.8 m / s)
t2 = 285.71 s
total time, t = t1 + t2
t = 498.1 s
Therefore the total average velocity is:
= (4800 m + 4800 m) / 498.1 s
= 19.27 m / s = 19.3 m / s
Answer:
19.3 m/s
The are parallel to each other because the are both straight horizontal lines
The correct answer is the last number line because with an inequality, the "equal to" sign below the "<" or ">" means the circle should be filled in. The line is traveling in a negative direction because the inequality says that n is less than -1.
The building is 300/50 = 6 times as high as the flagpole, so we expect its shadow to be 6 times as long: 6×30 ft = 180 ft.
96 cm^2
Each side has an area of 24 cm^2, so just multiply that by 4
