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3 years ago

WILL GIVE BRAINLIEST

Mathematics

2 answers:

bearhunter [10]3 years ago

7 0

Answer:

second question-heres answer

v20

convert v20 to a decimal 4.4721...

find the number in the hundredth place 7 and look one place to the right for the rounding digit 2.round up if this number is greater than or equal to 5 and round down if it less than 5

4.47

Tems11 [23]3 years ago

5 0

Answer:

Step-by-step explanation:

seen that before

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Adding 5+8+2 can be accomplished by

harkovskaia [24]

Answer:

8+5=13

13+2=15

your answer is 15

You have to add : )

Step-by-step explanation:

Hope this helps : )

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3 years ago

What is 0.67 x 0.3 <br> with explination please<br> correct answer ill mark brainlist

aleksklad [387]

Just multiply them together 0.67 x 0.3 = 0.201

7 0

3 years ago

Read 2 more answers

If one point on a horizontal line has coordinates (3, 2), which of the points below are also on the line? Select all that apply.

stepan [7]

Answer:

If the line is horizontal, then all that have a 2 in the Y space will apply because the line goes across meaning that it won't change on the vertical axis.

(5,2) and (-2, 2)

6 0

4 years ago

(1 point) a tank contains 1060 l of pure water. a solution that contains 0.06 kg of sugar per liter enters the tank at the rate

kirill115 [55]

(a) There is 0 kg of sugar in the tank at the beginning since it contains pure water at the start. The sugar only comes from the solution.

(b)

$S' = f(t,S) = \left(0.06 \dfrac{\text{kg}}{\text{L}}\right)\left(9\dfrac{\text{L}}{\text{min}}\right) - \left(\dfrac{S}{1060} \dfrac{\text{kg}}{\text{L}}\right)\left(9\dfrac{\text{L}}{\text{min}}\right) \ \Rightarrow \\ \\ S' = 0.54 \text{ kg}/\text{min} - \dfrac{9S}{1060}$

So yes, you enter S' = 0.54 - (9S/1060)

(c)

$\displaystyle\frac{dS}{dt} = 0.54 - \frac{9S}{1060} \ \Rightarrow\ \frac{dS}{dt} = \frac{572.4 - 9S}{1060}\ \Rightarrow\ \dfrac{dS}{572.4 - 9S} = \frac{1}{1060} dt\ \Rightarrow \\ \\
\int \dfrac{dS}{572.4 - 9S} = \int \frac{1}{1060} dt\ \Rightarrow\textstyle\ -\frac{1}{9}\ln|572.4 - 9S| = \frac{1}{1060}t + C \\ \\
S(0) = 0 \ \Rightarrow\ -\frac{1}{9}\ln|572.4 - 0| = \frac{1}{1060}(0) + C\ \Rightarrow\ C = -\frac{1}{9} \ln 572.4$

$-\frac{1}{9}\ln|572.4 - 9S| = \frac{1}{1060}t -\frac{1}{9} \ln 572.4\ \Rightarrow \\ \\
\ln|572.4 - 9S| = \ln 572.4 - \frac{9}{1060}t \ \Rightarrow \\ \\
|572.4 - 9S| = e^{\ln 572.4 - 9t/1060}\ \Rightarrow \\ \\
572.4 - 9S= \pm 572.4 e^{-9t/1060}\ \Rightarrow \\ \\
S = \frac{-1}{9}\left(-572.4 \pm 572.4 e^{-9t/1060}\right)$

But only (+) satisfies $S(0) = 0$

$S= -\frac{1}{9}\left(-572.4 + 572.4 e^{-9t/1060}\right) \\ \\
S= 63.6 - 63.6 e^{-9t/1060}\text{ kg}$

Enter in S = 63.6 - 63.6 * e^(-9t/1060)

3 0

3 years ago

Choose the correct way to revise the following run-on sentence.

Mila [183]

C SINCE IT IS A RUNOFF SENTENCE THERE SHOULD BE NO other marks

7 0

3 years ago