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GarryVolchara [31]
3 years ago
13

Solve: K(k+1) - 3k(k+1)

Mathematics
2 answers:
e-lub [12.9K]3 years ago
8 0

Answer:

-2k(k+1)

Step-by-step explanation:

Let's rewrite the equation to make it a little bit easier:

k(1+k) - 3k(1+k)

Then, factor out the common term k(1+k):

k(1+k)(1-3)

Simplify:

-2k(k+1)

Hope this helps!!

Leviafan [203]3 years ago
4 0

Answer:

k = 0 and k = -1

Step-by-step explanation:

To solve this, first distribute the terms inside the parenthesis. This should give you: k^2 + k - 3k^2 - 3k

Then, combine like terms to get: -2k^2 - 2k = 0

In this, you can factor out a -2k, giving you the new equation: -2k (k + 1) = 0

Set -2k equal to 0 and k + 1 equal to 0.

-2k = 0

Divide -2 onto both sides, leaving you with k = 0

k + 1 = 0

Subtract 1 from both sides, leaving you with k = -1

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Sunny_sXe [5.5K]

Answer:

Part 1) "a" value is 2

Part 2) The vertex is the point (1,8)

Part 3) The equation of the axis of symmetry is x=1

Part 4) The vertex is a minimum

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Step-by-step explanation:

we know that

The equation of a vertical parabola into vertex form is equal to

y=a(x-h)^{2}+k

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(h,k) is the vertex of the parabola

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so

x=h

In this problem we have

y=2(x-1)^{2}+8 -----> this is the equation in vertex form of a vertical parabola

The value of a=2

so

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The vertex is the point (1,8)

so

(h,k)=(1,8)

The equation of the axis of symmetry is x=1

The equation of a vertical parabola in standard form is equal to

y=ax^{2}+bx+c

Convert vertex form in standard form

y=2(x-1)^{2}+8

y=2(x^{2}-2x+1)+8

y=2x^{2}-4x+2+8

y=2x^{2}-4x+10

see the attached figure to better understand the problem

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