Average (mean) = (sum of all the data) / (# of data)
sum of all the data = (average)(# of data)
Thus for 100 students with an average of 93,
sum of all data = (93)(100) = 9300
and for 300 students with an average of 75,
sum of all data = (75)(300) = 22500
Therefore you would expect the overall average to be
(9300 + 22500) / (100 + 300) = 79.5 %
Now if there are x # of advanced students and y # of regular students, then
x + y = 90 (total # of students) and 93x + 75y = 87(x + y) (overall average)
The second equation can be simplified to x - 2y = 0
Subtracting the two equations yields
x = 60 and y = 90
Therefore you would need 60 advanced and 30 regular students.
Hello,
Answer is Dsince y=k(x-2)²-5 and if k=1 ==>D.
We are given
total number of friends =6
the cost of one admission is $9.50
now, we can find total cost for admission
total cost for admission= total number of friends*cost of one admission
total cost for admission=6*9.50
we are given
cost for one ride on the Ferris wheel is $1.50
now, we can find total cost for Ferris wheel ride
total cost for Ferris wheel ride= total number of friends*cost of one ride
total cost for Ferris wheel ride=6*1.50
now, we can find total cost
total cost =total cost for admission+total cost for Ferris wheel ride
total cost
now, we can solve it
total cost
total cost
total cost
so, the total cost is $66...........Answer
How many dekameters are in 225 millimeters? Use the metric table to help answer the question.Metric Tablekilo-hecto-deka-unitdeci-centi-milli-1,0001001010.10.010.001