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grandymaker [24]
3 years ago
8

There were 630 concert tickets sold. Each ticket cost $21. How much money was raised from selling the tickets

Mathematics
1 answer:
Andrew [12]3 years ago
8 0

Answer:

$13,230

Step-by-step explanation:

you need to multiply the cost of the ticket by the amount of tickets sold,

630 x 21 = $13,230

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Approximate each square root to the nearest tenth<br><br> 130<br><br> 85
Y_Kistochka [10]

130 = 11.4

85 = 9.2

hope this helps!!

6 0
3 years ago
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Mr. Smith has an online cooking show. Before he films an episode about baking the perfect pound cake, he prepares his ingredient
Leviafan [203]

Answer:

15

Step-by-step explanation:

We are told in the question that:

Mr Smith's recipe calls for 2 1/2 cups of sugar for the cake and 1 1/4 cups of sugar for the vanilla glaze.

Step 1

We add up the total amount of sugar he would need

2 1/2 + 1 1/4

(2 + 1) + (1/2 + 1/4)

= 3 + (2 + 1/4)

= 3 3/4 cups of sugar.

Step 2

How many 1/4 cup scoops of sugar does he need?

This is calculated as:

3 3/4 cups of sugar ÷ 1/4

= 15/4 ÷ 1/4

= 15/4 × 4

= 15

Therefore, he would be needing 15 , 1/4 cup scoop of sugar

6 0
3 years ago
Given O A ‾ ⊥ O C ‾ OA ⊥ OC start overline, O, A, end overline, \perp, start overline, O, C, end overline m ∠ B O C = 6 x − 6 ∘
Lelu [443]

Answer:

m∠BOC = 40°

Step-by-step explanation:

Given O A ‾ ⊥ O C ‾ OA ⊥ OC m∠BOC=6x−6 ∘

m∠AOB=5x+8 ∘

Find m ∠ B O C:

This means that: m∠BOC and m∠AOC intersect at a right angle.

Hence:

m∠BOC + m∠AOC = 90°

Step 1

Solving for x

6x - 6 + 5x + 8 = 90°

11x -2 = 90°

11x = 90 - 2

11x = 88

x = 88/11

x = 8

Step 2

Solving for m∠BOC

m∠BOC = 6x - 8

m∠BOC = 6(8) - 8

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7 0
3 years ago
The number of bacteria in a certain culture doubled every hour. If there were 30 bacteria present in the culture initially, how
vichka [17]

Answer:

The number of bacteria after 8th will be 3840

Step-by-step explanation:

Given the initially 30 bacteria present in the culture.

Also, the number of bacteria got doubled every hour.

So, using the equation

A=A_0r^{n-1}

Where A is number of bacteria after n hours.

A_0 is bacteria present initially.

r is the common ration, in our problem it is given that bacteria doubles every hour. So, r=2

And n is the number of hours. In our problem we need amount of bacteria at the end of 8th hours. So, n=8

Plugging values in the formula we get,

A=30(2)^{8-1}\\A=30\times 2^7\\A=30\times 128\\A=3840

So, number of bacteria after 8th will be 3840

3 0
3 years ago
Which of the following would be an acceptable first step in simplifying the expression (cot x)/(1 - csc x) ?
alukav5142 [94]

Answer:

cotx(1+csc x)/(1-csc x)(1+csc x)

5 0
2 years ago
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