Honestly I don’t even know what this is sorry I tried
For this type of problem you would have to move the decimal as many places to the right as needed to make the divisor a whole number the you would move the dividend the same amount of times even if it is a whole number . Then you use what you have to divide normally. Hope this helps!
Step-by-step explanation:
SAS is Side - Angle (between the sides) - Side
BC and CD are shown to be congruent with the markers that cross the line segments.
AC and AC are the same because they are the same.
The only things needed are the congruent angles between the sides.
The angles are ACD and ACB, because those are the angles between AC and BC and AC and CD.
Answer:
3) Midpoint is (-4,0.5)
Option A is correct.
4) Midpoint is (2.5,0)
Option B is correct.
5) The factors are (x+4)(x-7)
Option C is correct.
6) The factors are (x+4)(x+2)
Option A is correct.
Step-by-step explanation:
Question 3
Find midpoint of the following:
(2,-7), (-10,8)
The formula used to find midpoint is: 
We have 
Putting values and finding midpoint

So, Midpoint is (-4,0.5)
Option A is correct.
Question 4
Find midpoint of the following:
(2,-10), (3,10)
The formula used to find midpoint is: 
We have 
Putting values and finding midpoint

So, Midpoint is (2.5,0)
Option B is correct.
Question 5
Factor each completely

We will break the middle term and find factors

So, the factors are (x+4)(x-7)
Option C is correct.
Question 6
Factor each completely

We will break the middle term and find factors

So, the factors are (x+4)(x+2)
Option A is correct.