Answer:
-4x(3x+4)
Step-by-step explanation:
You have to undo the problem, I will show you how this problem looks if you solve it (the answer i guess? id.k it is hard to explain any other way)
So first we use distributive property-
-4x *3x=-12x^2
-4x*4=-16x
-12x^2-16x And now we have the problem we started with!
Answer:7m^5 - 3m^3 + 9
Step-by-step explanation: You’d have to remove the brackets, but remember that the second has to have everything multiplied by -1, because there’s a minus sign in front of the second bracket. Then you’d group like terms, then add or subtract. Here’s the step by step
6m^5 + 3 - m^3 - 4m + m^5 - 2m^3 + 4m + 6
2. 6m^5 + m^5 - 2m^3 - m^3 + 4m - 4m + 6 + 3
Subtract or add what’s needed, which would be figures with the same variable and coefficient.
3. 7m^5 - 3m^3 + 9
After this, there’s nothing you can add, since the remaining figures don’t have the same variable.
Hope it’s clear and this wasn’t that long
Answer:
x=50
Step-by-step explanation:
x in (-oo:+oo)
(2/5)*x+10 = 30 // - 30
(2/5)*x-30+10 = 0
2/5*x-20 = 0 // + 20
2/5*x = 20 // : 2/5
x = 20/2/5
x = 50
x = 50
Given the table below which contains data from 200 endothemic reactions involving <span>sodium bicarbonate:
![\begin{tabular} {|c|c|} Final Temperature Conditions&Number of Reactions\\[1ex] 266 K&48\\ 271 K&60\\ 274 K&92 \end{tabular}](https://tex.z-dn.net/?f=%5Cbegin%7Btabular%7D%0A%7B%7Cc%7Cc%7C%7D%0AFinal%20Temperature%20Conditions%26Number%20of%20Reactions%5C%5C%5B1ex%5D%0A266%20K%2648%5C%5C%0A271%20K%2660%5C%5C%0A274%20K%2692%0A%5Cend%7Btabular%7D)
We find the probability distribution function as follows:
Let X denote the final temperature, then
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