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lubasha [3.4K]
3 years ago
9

If the graphs of the linear equations in a system are parallel,what does that mean about the possible solution (s) of the system

?
Mathematics
2 answers:
Sergio039 [100]3 years ago
7 0

Answer:

that answer would be linear

Step-by-step explanation:

if both of the lines are parallel to each other then they can never touch, so no contact with each other means no answer

Black_prince [1.1K]3 years ago
5 0

Answer:

it means that there will be no solution .

<h2><em>hope this helped <3</em></h2><h2><em /></h2>

<em>-bubb0</em>

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erastova [34]
On the 14 week Juan will save $ 52 because each 3 week he earns 3.
So you do 9 divide by 3 and get 3. Then you do 3 times 2 and get 6.
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Vincent wrote an example of a proportion on the board.
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Answer:

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Step-by-step explanation:

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3 years ago
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How do you solve this?
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4 0
3 years ago
A family has a bike rack that fits seven bikes, but they only have 5 bikes. How many ways can they fit these bikes on the rack
stellarik [79]

Answer:

x=21 ways

Step-by-step explanation:

From the question we are told that:

Bike space N=7

Number of Bike n=5

Generally the equation for This combination is mathematically given by

 x=^NC_n

 x=^7C_5

 x= \frac{7!}{5!2!}

 x= 7*6/2  

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6 0
3 years ago
Compute the Taylor expansion of order n=2 of the function sin(xy) at x=0 and y=0
artcher [175]

Answer:

f(x, y) = Sin(x*y)

We want the second order taylor expansion around x = 0, y = 0.

This will be:

f(x,y) = f(0,0) + \frac{df(0,0)}{dx} x + \frac{df(0,0)}{dy} y + \frac{1}{2} \frac{d^2f(0,0)}{dx^2} x^2 +\frac{1}{2} \frac{d^2f(0,0)}{dy^2}y^2  + \frac{d^2f(0,0)}{dydx} x*y

So let's find all the terms:

Remember that:

\frac{dsin(ax)}{dx}  = a*cos(ax)

\frac{dcos(ax)}{dx} = -a*cos(ax)

f(0,0) = sin(0*0) = 1.

\frac{df(0,0)}{dx}*x = y*cos(0*0)*x = x*y

\frac{df(0,0)}{dy} *y = x*cos(00)*y = x*y

\frac{1}{2} \frac{d^2f(0,0)}{dx^2}*x^2 =  -\frac{1}{2}  *y^2*sin(0*0)*x^2 = 0

\frac{1}{2} \frac{d^2f(0,0)}{dy^2}*y^2 =  -\frac{1}{2}  *x^2*sin(0*0)*y^2 = 0

\frac{d^2f(0,0)}{dxdy} x*y = (cos(0*0) -x*y*sin(0*0))*x*y = x*y

Then we have that the taylor expansion of second order around x = 0 and y = 0 is:

sin(x,y) = x*y + x*y + x*y = 3*x*y

6 0
3 years ago
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