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3 years ago

5

Find the 59th term of the arithmetic sequence 29,37,45,...

1 answer:

liberstina [14]3 years ago

4 0

Answer:

13,456

Step-by-step explanation:

Tn= a+(n-1)d

a is the first term, n is the given number and d is the common difference. d is given by subtracting the first term from the second term or the second from the third. Therefore the the 59th term of the sequence 29, 37, 45 is,

Tn= 29+(59-1)8

=29(58)8

=13,456

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love history [14]

<h3> The greatest number is $1.997 \times 10^2$ </h3>

<em><u>Solution:</u></em>

<em><u>Given that the numbers are:</u></em>

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Step-by-step explanation:

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