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3 years ago

I really need help with this ?

Mathematics

1 answer:

Digiron [165]3 years ago

8 0

The answer is g. 47.1

you use the formula
c= π d
then plug is 15 for d and you should get the answer

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KengaRu [80]

Answer:

one

Step-by-step explanation:

they meet at only one point, thus their system of equations has as solution only those coordinates.

8 0

2 years ago

Find the exact length of the curve. x=et+e−t, y=5−2t, 0≤t≤2 For a curve given by parametric equations x=f(t) and y=g(t), arc len

Rama09 [41]

The length of a curve C parameterized by a vector function r(t) = x(t) i + y(t) j over an interval a ≤ t ≤ b is

$\displaystyle\int_C\mathrm ds = \int_a^b \sqrt{\left(\frac{\mathrm dx}{\mathrm dt}\right)^2+\left(\frac{\mathrm dy}{\mathrm dt}\right)^2} \,\mathrm dt$

In this case, we have

x(t) = exp(t ) + exp(-t ) ==> dx/dt = exp(t ) - exp(-t )

y(t) = 5 - 2t ==> dy/dt = -2

and [a, b] = [0, 2]. The length of the curve is then

$\displaystyle\int_0^2 \sqrt{\left(e^t-e^{-t}\right)^2+(-2)^2} \,\mathrm dt = \int_0^2 \sqrt{e^{2t}-2+e^{-2t}+4}\,\mathrm dt$

$=\displaystyle\int_0^2 \sqrt{e^{2t}+2+e^{-2t}} \,\mathrm dt$

$=\displaystyle\int_0^2\sqrt{\left(e^t+e^{-t}\right)^2} \,\mathrm dt$

$=\displaystyle\int_0^2\left(e^t+e^{-t}\right)\,\mathrm dt$

$=\left(e^t-e^{-t}\right)\bigg|_0^2 = \left(e^2-e^{-2}\right)-\left(e^0-e^{-0}\right) = \boxed{e^2-\frac1{e^2}}$

5 0

2 years ago

A square park is 75 m long. Find the area of the park.

Inga [223]

5625 m^2

If is is square, all sides must be congruent (all sides are 75m). To find area, you multiply width x length (how long). Therefore:

75m x 75m = 5626 m^2

3 0

2 years ago

Each time Sarah went to the Candy Shoppe, she bought b bags of M&Ms. Write an expression for how many bags she will buy if s

andrey2020 [161]

Answer:

$b \times 2$

Step-by-step explanation:

The reason is because you don't know the Inital amount she bought and because she visits two days in a row you would multiply

6 0

9 months ago

I don't understand this.

sladkih [1.3K]

You mean the word or number

7 0

3 years ago