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amid [387]
3 years ago
6

Marlon and Michelle have to graph a function with the equation y=x2and are having to debate about which is the most important el

ement to get started, the domain or the range . which of them is correct?

Mathematics
1 answer:
Usimov [2.4K]3 years ago
5 0

Answer:

Correct answer is the domain.

Step-by-step explanation:

A domain is the input set of a function.

A range is the output set of the function.

It is more  important to know the domain of the function to be able to determine the corresponding output set so the function can be graphed. To start with the domain is very useful because every domain element has a corresponding unique output element.

Suppose you started with the range element of 9. The input set for an output of 9 is {-3,3}. This makes it hard to match up the elements. This example highlights why it is important to start with the domain rather than the range.

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Find the unit tangent vector T and the principal unit normal vector N for the following parameterized curve.
const2013 [10]

Answer:

a.

T(t) = ( -sin(t^2), cos(t^2) )\\\\N(t) = T'(t) / |T'(t) |  =   (-cos(t^2) , -sin(t^2))

b.

T(t) =r'(t)/|r'(t)| =  (2t/ \sqrt{4t^2   + 36} , -6/\sqrt{4t^2   + 36},0)

N(t) =T(t)/|T'(t)| =  (3/(9 + t^2)^{1/2} , t/(9 + t^2)^{1/2},0)

Step-by-step explanation:

Remember that for any curve      r(t)  

The tangent vector is given by

T(t) = \frac{r'(t) }{| r'(t)| }

And the normal vector is given by

N(t) = \frac{T'(t)}{|T'(t)|}

a.

For this case, using the chain rule

r'(t) = (  -10*2tsin(t^2) ,   102t cos(t^2)   )\\

And also remember that

|r'(t)| = \sqrt{(-10*2tsin(t^2))^2  +  ( 10*2t cos(t^2) )^2} \\\\       = \sqrt{400 t^2*(  sin(t^2)^2  +  cos(t^2) ^2 })\\=\sqrt{400t^2} = 20t

Therefore

T(t) = r'(t) / |r'(t) | =  (  -10*2tsin(t^2) ,   10*2t cos(t^2)   )/ 20t\\\\ = (  -10*2tsin(t^2)/ 20t ,   10*2t cos(t^2) / 20t  )\\= ( -sin(t^2), cos(t^2) )

Similarly, using the quotient rule and the chain rule

T'(t) = ( -2t cos(t^2) , -2t sin(t^2))

And also

|T'(t)| = \sqrt{  ( -2t cos(t^2))^2 + (-2t sin(t^2))^2} = \sqrt{ 4t^2 ( ( cos(t^2))^2 + ( sin(t^2))^2)} = \sqrt{4t^2} \\ = 2t

Therefore

N(t) = T'(t) / |T'(t) |  =   (-cos(t^2) , -sin(t^2))

Notice that

1.   |N(t)| = |T(t) | = \sqrt{ cos(t^2)^2  + sin(t^2)^2 } = \sqrt{1} =  1

2.   N(t)*T(T) = cos(t^2) sin(t^2 ) - cos(t^2) sin(t^2 ) = 0

b.

Simlarly

r'(t) = (2t,-6,0) \\

and

|r'(t)| = \sqrt{(2t)^2   + 6^2} = \sqrt{4t^2   + 36}

Therefore

T(t) =r'(t)/|r'(t)| =  (2t/ \sqrt{4t^2   + 36} , -6/\sqrt{4t^2   + 36},0)

Then

T'(t) = (9/(9 + t^2)^{3/2} , (3 t)/(9 + t^2)^{3/2},0)

and also

|T'(t)| = \sqrt{ ( (9/(9 + t^2)^{3/2} )^2 +   ( (3 t)/(9 + t^2)^{3/2})^2  +  0^2 }\\= 3/(t^2 + 9 )

And since

N(t) =T(t)/|T'(t)| =  (3/(9 + t^2)^{1/2} , t/(9 + t^2)^{1/2},0)

6 0
3 years ago
1) 3+5+8° +10+6<br> I<br> i need help
diamong [38]

Answer:

36°

Step-by-step explanation:

3+5+8°+10+6= 36°

<em>Hope</em><em> </em><em>this</em><em> </em><em>helps</em><em> </em>

5 0
3 years ago
Solve the equation 4-2(x+7)=3(x+5) =
kumpel [21]

Hi there!


To solve this equation, I first would like to warn you about the long answer I am about to post for you. I'll be putting in very detailed steps for you, showing you how to simplify and distribute numbers, etc. :)


Let us solve your equation step-by-step.


Step 1) Simplify both sides of the equation.


To simplify this, we will...


4 + (-2) (x) + (-2) (7) = (3) (x) + (3) (5)


4 + - 2x + - 14 = 3x + 15


(-2x) + (4 + - 14) = 3x + 15


Now, we combine Like Terms...


-2x + - 10 = 3x + 15


-2x - 10 = 3x + 15


Fwew! That was probably going to be the longest step here!


Step 2) Subtract 3x from both sides.


- 2x - 10 - 3x = 3x + 15 - 3x


- 5x - 10 = 15


Step 3) Add 10 to both sides.


- 5x - 10 + 10 = 15 + 10


- 5x = 25


Step 4) Divide both sides by -5.


-5x/-5 = 25/-5


So, our final answer is x = -5.


Hope this helps!

Message me if you need anything else! I'd be happy to help! :D

8 0
3 years ago
Read 2 more answers
What is the slope of the line shown in the graph? <br> A.-3/2<br> B.-1/2<br> C.3/2
Varvara68 [4.7K]
I think answer is A
Because slope=rise/run
Rise is 3
Run is 2
But it will be negative because of the direction of slope
6 0
3 years ago
How are the shapes alike
Andrews [41]

Answer:

Each circle (A, B, and C) contain shapes that all share at least one characteristic. Some shapes are contained in more than one circle because they share more than one characteristic. For example, shape 3 fits the rule for circles A and B, but not circle C. It lies within circles A and B, but not circle C.

Step-by-step explanation:

3 0
3 years ago
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