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PIT_PIT [208]
3 years ago
5

Explain how to write the solution to the given inequality in interval notation.

Mathematics
2 answers:
dedylja [7]3 years ago
6 0
<h2>Answer:</h2>

The solution to the given inequality in interval notation is:

                          [-4,1]

<h2>Step-by-step explanation:</h2>

From the number line graph that is provided to us we see that the shaded region is to the right of -4 and to the left of -1.

Also, there are closed circles at -4 and -1.

This means that the solution set is the set of all the real values between -4 and -1 inclusive.

( If there would be open circles at -4 and -1 then those would not be included in the solution set )

i.e. in interval form the solution set is:

               [-4,-1]

son4ous [18]3 years ago
4 0
It is negative 4 and negative 1 between those
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<u>Answer:</u>

<u>For a:</u> The probability of getting a red or blue ball is 0.48

<u>For b:</u> The probability of getting a white, blue or orange ball is 0.81

<u>For c:</u> The probability of getting neither white or orange ball is 0.48

<u>Step-by-step explanation:</u>

Probability is defined as the extent to which an event is likely to occurs. It is measured by the ratio of the favorable outcomes to the total number of possible outcomes.

\text{Probability}=\frac{\text{Number of favorable outcomes}}{\text{Total number of favorable outcomes}}     .......(1)

We are given:

Number of red balls in a box = 12

Number of white balls in a box = 18

Number of blue balls in a box = 19

Number of orange balls in a box = 15

Total balls in a box = [12 + 18 + 19 + 15] = 64

  • <u>For a:</u>

Number of favorable outcomes (ball must be red or blue) = [12 + 19] = 31

Total number of outcomes = 64

Putting values in equation 1, we get:

\text{Probability of getting a red or blue ball}=\frac{31}{64}=0.48

  • <u>For b:</u>

Number of favorable outcomes (ball must be white or blue or orange) = [18 + 19 + 15] = 52

Total number of outcomes = 64

Putting values in equation 1, we get:

\text{Probability of getting a white or blue or orange ball}=\frac{52}{64}=0.81

  • <u>For c:</u>

Number of favorable outcomes (ball must be white or orange) = [18 + 15] = 33

Total number of outcomes = 64

Putting values in equation 1, we get:

\text{Probability of getting a white or orange ball}=\frac{33}{64}=0.52

Probability of getting a ball which is neither white or orange = [1 - (Probability of getting a white or orange ball)] = [1 - 0.52] = 0.48

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