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lana66690 [7]
3 years ago
13

Find x, when p(x) = -1,

Mathematics
1 answer:
Neporo4naja [7]3 years ago
8 0

Answer:

positive or negative 4

Step-by-step explanation:

p(x) is another form of saying y. plug in -1 as the y value. then look where on the graph it touches the line

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What is the length of the missing leg?*<br> 60 cm<br> 36 cm<br><br> B=?
OverLord2011 [107]

Answer:

i think the leg is 60 cm

Step-by-step explanation:

sana po makatulong

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In the figure below, mZAHE = (6x + 7)º
Andru [333]

Answer:

Step-by-step explanation:

∠AHE + ∠AHK = 180    {linear pair}

6x + 7 + 35 = 180

6x + 42 = 180

          6x = 180 - 42

          6x = 138

            x = 138/6

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Find the value of x.<br> A. 22.5<br> B.40<br> C.45<br> D.95
Troyanec [42]

Answer:

x = 22.5

Step-by-step explanation:

The tangent- secant angle x is half the difference of the measures of the intercepted arcs, that is

\frac{1}{2} (4x + 5 - 50 ) = x ( multiply both sides by 2 )

4x - 45 = 2x ( subtract 2x from both sides )

2x - 45 = 0 ( add 45 to both sides )

2x = 45 ( divide both sides by 2 )

x = 22.5

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3 years ago
The area of the united states is 3,794,100 square miles. which is the best estimation of this area?
ludmilkaskok [199]
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3 years ago
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Pyramid A has a triangular base where each side measures 4 units and a volume of 36 cubic units. Pyramid B has the same height,
omeli [17]

Answer:

The volume of pyramid B is 81 cubic units

Step-by-step explanation:

Given

<u>Pyramid A</u>

s = 4 -- base sides

V = 36 -- Volume

<u>Pyramid B</u>

s = 6 --- base sides

Required

Determine the volume of pyramid B <em>[Missing from the question]</em>

From the question, we understand that both pyramids are equilateral triangular pyramids.

The volume is calculated as:

V = \frac{1}{3} * B * h

Where B represents the area of the base equilateral triangle, and it is calculated as:

B = \frac{1}{2} * s^2 * sin(60)

Where s represents the side lengths

First, we calculate the height of pyramid A

For Pyramid A, the base area is:

B = \frac{1}{2} * s^2 * sin(60)

B = \frac{1}{2} * 4^2 * \frac{\sqrt 3}{2}

B = \frac{1}{2} * 16 * \frac{\sqrt 3}{2}

B = 4\sqrt 3

The height is calculated from:

V = \frac{1}{3} * B * h

This gives:

36 = \frac{1}{3} * 4\sqrt 3 * h

Make h the subject

h = \frac{3 * 36}{4\sqrt 3}

h = \frac{3 * 9}{\sqrt 3}

h = \frac{27}{\sqrt 3}

To calculate the volume of pyramid B, we make use of:

V = \frac{1}{3} * B * h

Since the heights of both pyramids are the same, we can make use of:

h = \frac{27}{\sqrt 3}

The base area B, is then calculated as:

B = \frac{1}{2} * s^2 * sin(60)

Where

s = 6

So:

B = \frac{1}{2} * 6^2 * sin(60)

B = \frac{1}{2} * 36 * \frac{\sqrt 3}{2}

B = 9\sqrt 3

So:

V = \frac{1}{3} * B * h

Where

B = 9\sqrt 3 and h = \frac{27}{\sqrt 3}

V = \frac{1}{3} * 9\sqrt 3 * \frac{27}{\sqrt 3}

V = \frac{1}{3} * 9 * 27

V = 81

6 0
3 years ago
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