The average speed of Joshua during that time is 2500 m/h.
Explanation:
It is given that Joshua started cycling at 5:15 pm. By 8:09 pm he has covered a distance of 7250 m.
The total time taken by Joshua from 5:15 pm to 8:09 pm is
Dividing we get,
Adding, we have,
Thus, the total time taken by Joshua is 
To determine the average speed we use the formula,
where 
and 
Hence, substituting the values we have,
Dividing, we get,
Thus, the average speed of Joshua during that time is 2500 m/h.
Answer:
i6 sqrt 5
Step-by-step explanation:
It cannot be 12i sqrt 5 as this is 26.8326....
it cannot be 18i sqrt 5 as this is 40.249...
It cannot be 8i sqrt 5 as this is 17.888....
It cnanot be 8i sq rt 10 as this is 25.298....
i6 sq rt 5 = sqrt -180
Answer:
Area of the dilation = 10.8 square inches
Step-by-step explanation:
Given the original dimension
Length = 12inches
Width = 10inches
If they are dilated by a factor of 0.3
New length = 0.3 * 12 = 3.6in
New width = 0.3 * 10 = 3in
Area of the dilation = 3.6 * 3
Area of the dilation = 10.8 square inches
Yes cause he can decrease the perimeter in any way and it would change the area and idk the other 2 in the front
