This is not a full question. If you were given the amount at the begining of 1970 (we'll call it x) and the amount at the end of 1980 (we'll call it y), we should solve them accordingly:
y-x=? (calling the answer a)
a/y=%(not answer yet, call this b)
b+100=answer
Answer: koh-rien
Step-by-step explanation:
Answer:
MAD is 5.12
Step-by-step explanation:
The following data were obtained from the question:
42, 50, 54, 38, 48
Next, we shall determine the mean of the data. This can be obtained as follow:
Mean = summation X / n
n is the number of the data.
Summation X = 42 + 50 + 54 + 38 + 48
Summation X = 232
n = 5
Mean = summation X / n
Mean = 232 / 5
Mean = 46.4
Therefore, the mean of the data is 46.4
Finally, we shall determine the mean absolute deviation (MAD) of the data as follow:
MAD = summation |mean – X| /n
MAD = (|(46.4 – 42) + (46.4 – 50) + (46.4 – 54) + (46.4 – 38) + (46.4 – 48|) /5
MAD = |4.4 + 3.6 + 7.6 + 8.4 + 1.6| /5
MAD = 25.6/5
MAD = 5.12
Therefore, the mean absolute deviation (MAD) is 5.12
Negative four times 3p is -12p so then -12p-7 <5. Then add 7 to five and get -12p<12. Divide by -12, change direction of symbol because you are dividing by a negative and get p>-1.
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