The answer is C, you can do this by doing FOIL
You form a rhombus.
Draw an equilateral triangle, and then mirror it around its base. All the sides are clearly equal, because they are all sides of the same equilateral triangle.
Moreover, the top and bottom angle are 60°, because they are angles of an equilateral triangle, while the left and right angles are 120, because they're 60+60 angles.
Answer:
It is false: -16>-15 is not true
Answer:
0.629 or 0.795
Step-by-step explanation:
Answer:
ASA and AAS
Step-by-step explanation:
We do not know if these are right triangles; therefore we cannot use HL to prove congruence.
We do not have 2 or 3 sides marked congruent; therefore we cannot use SSS or SAS to prove congruence.
We are given that EF is parallel to HJ. This makes EJ a transversal. This also means that ∠HJG and ∠GEF are alternate interior angles and are therefore congruent. We also know that ∠EGF and ∠HGJ are vertical angles and are congruent. This gives us two angles and a non-included side, which is the AAS congruence theorem.
Since EF and HJ are parallel and EJ is a transversal, ∠JHG and ∠EFG are alternate interior angles and are congruent. Again we have that ∠EGF and ∠HGJ are vertical angles and are congruent; this gives us two angles and an included side, which is the ASA congruence theorem.
