Answer: 1 what do u think to help u
Answer:
50%
Explanation:
The markup is the difference between the selling price and the cost price. If the mark up is greater than zero, it means there is a profit, if the markup is less than 0, it means there is a loss and if the markup is equal to 0, it means there is breakeven.
Percentage markup = (markup/cost price) * 100%
Selling price - cost price = markup
15 - cost price = 5
cost price = 10
Percentage markup = (markup/cost price) * 100% = (5/10) * 100% = 50%
Answer: If a customer orders more than four pizzas, the program should deduct 10% from the cost of the order. Modify the program appropriately, and then save, run, and test it.
<span>Barricades, vertical panels, drums, and cones in construction zones are known as channelizing devices. They a</span>re used in construction and maintenance work areas <span> to notify drivers or passengers of unusual or potentially dangerous conditions in or near work areas.
</span>A barricade is a portable or fixed device having from one to three rails with appropriate markings. It is used to control traffic by closing, restricting, or delineating all or a portion of the right-of-way.<span>Drums are most commonly used to channelize or delineate traffic flow but may also be used singly or in groups to mark specific locations.</span>
Stack is LIFO data structure (Last In First Out) where the last element entered in stack will be the last one to be out of stack. It has three operations: push() : used to insert an element in stack, pop() : used to delete an element from the stack, top() : used to return the top of the stack i.e. the newest member of the stack. All these operations will take place at the top.
<u>Explanation:</u>
Now, looking at the program, x and y are initialized the values of 2 and 3 respectively. The stack pushes 8 onto the stack making it the first member of the stack. Then the value of x which is 2 is pushed onto the stack. Next, (x+5) = (2+5) = 7 is pushed onto the stack.
Pop() is used to delete hence 7 is popped out from the stack. top() is assigned to y which is 2 in this case and again 2 is popped out from the stack. Now, (x+y) = (2+2) = 4 is pushed onto the stack. And the top() is assigned to x which is 4. 4 is again popped out from the stack. Hence the value of x is 4.
