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iris [78.8K]
3 years ago
14

What is a quasi vpn?

Computers and Technology
1 answer:
Natasha2012 [34]3 years ago
6 0

Answer:

i don't think there is such thing as a quasi vpn

Explanation:

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The theory of continental drift suggests that at one time,
MakcuM [25]
The Continents were all joined into one land mass
3 0
4 years ago
Read 2 more answers
Kelley is managing a project to deploy the company's new application offering by using a cloud service provider for the platform
Lapatulllka [165]

Answer:

Analyse performance

Explanation:

During the deployment of new services to a certain Platform such as the cloud which is geared towards enhancing scalability which is the ability of platforms to accommodate larger load level are serve an increased number of consumers. These will require these platforms to be Analysed as per performance in other to evaluate them . Through performance analysis, elasticity may need to be tweaked by dynamic rearrangement of the different modules, hardwares in other to ensure that the platform delivers at the required level to serve the increased number of consumers.

3 0
3 years ago
Given parameters b and h which stand for the base and the height of an isosceles triangle (i.e., a triangle that has two equal s
schepotkina [342]

Answer:

The area of the triangle is calculated as thus:

Area = 0.5 * b * h

To calculate the perimeter of the triangle, the measurement of the slant height has to be derived;

Let s represent the slant height;

Dividing the triangle into 2 gives a right angled triangle;

The slant height, s is calculated using Pythagoras theorem as thus

s = \sqrt{b^2 + h^2}

The perimeter of the triangle is then calculated as thus;

Perimeter = s + s + b

Perimeter = \sqrt{b^2 + h^2} + \sqrt{b^2 + h^2} +b

Perimeter = 2\sqrt{b^2 + h^2} + b

For the volume of the cone,

when the triangle is spin, the base of the triangle forms the diameter of the cone;

Volume = \frac{1}{3} \pi * r^2 * h

Where r = \frac{1}{2} * diameter

So, r = \frac{1}{2}b

So, Volume = \frac{1}{3} \pi * (\frac{b}{2})^2 * h

Base on the above illustrations, the program is as follows;

#include<iostream>

#include<cmath>

using namespace std;

void CalcArea(double b, double h)

{

//Calculate Area

double Area = 0.5 * b * h;

//Print Area

cout<<"Area = "<<Area<<endl;

}

void CalcPerimeter(double b, double h)

{

//Calculate Perimeter

double Perimeter = 2 * sqrt(pow(h,2)+pow((0.5 * b),2)) + b;

//Print Perimeter

cout<<"Perimeter = "<<Perimeter<<endl;

}

void CalcVolume(double b, double h)

{

//Calculate Volume

double Volume = (1.0/3.0) * (22.0/7.0) * pow((0.5 * b),2) * h;

//Print Volume

cout<<"Volume = "<<Volume<<endl;

}

int main()

{

double b, h;

//Prompt User for input

cout<<"Base: ";

cin>>b;

cout<<"Height: ";

cin>>h;

//Call CalcVolume function

CalcVolume(b,h);

//Call CalcArea function

CalcArea(b,h);

//Call CalcPerimeter function

CalcPerimeter(b,h);

 

return 0;

}

3 0
3 years ago
BRAINLIEST
Brilliant_brown [7]

Answer:

1. Don't

2. Do

3. Don't

4. Don't

5. Do

Hope it helps.......

3 0
3 years ago
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Write a function sample_median(n,P) that generates n random values using distribution P and returns the median of the collected
TiliK225 [7]

Answer:

import numpy as np

def sample_median(n, P):  

   return np.median( np.random.choice ( np.arange (1, len(P) + 1 ), n, p = P ) )

print(sample_median(10,[0.1 0.2 0.1 0.3 0.1 0.2]))

print(sample_median(10,[0.1 0.2 0.1 0.3 0.1 0.2]))

print(sample_median(5, [0.3,0.7])

print(sample_median(5, [0.3,0.7])

Explanation:

  • Bring in the numpy library to use the median function provided by the numpy library.
  • Define the sample_median function that takes in 2 parameters and returns the median with the help of built-in random, choice and arrange functions.
  • Call the sample_median function by providing some values to test and then display the results.    

Output:

4.5

4.0

2.0

1.0

7 0
3 years ago
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