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iris [78.8K]
3 years ago
14

What is a quasi vpn?

Computers and Technology
1 answer:
Natasha2012 [34]3 years ago
6 0

Answer:

i don't think there is such thing as a quasi vpn

Explanation:

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Continuous data
Elena-2011 [213]

Answer: Could be subdivided into smaller and smaller units.

Explanation:

 The continuous data are basically measured in the small units and can be easily subdivided into smaller parts without changing their actual meaning.

The continuous data also contain numeric value and can be divided into smaller and finer meaningful parts.

The continuous data can be measured according to the precision of the system. The size and volume are the example of the continuous data.

7 0
3 years ago
You often need to have several applications open at the same time. Which requirement is related to this need?
Musya8 [376]

Answer:

processor speed is the answer but not sure

5 0
3 years ago
If a clean install is performed on a hard drive with a previous install of windows and the drive is not re-formatted during the
Tpy6a [65]
Either wiped off the drive, or right next to the new ones, I do not recommend keeping the old files.
3 0
3 years ago
Create a program that has at least three classes. The class with main. A class that defines a Name (first name, middle name, and
Bond [772]

Answer:

See attached file for complete detailed code.

Explanation:

See attached file.

Download txt
3 0
3 years ago
Write a function which the counts the number of odd numbers and even numbers currently in the stack and prints the results.
Lerok [7]

Answer:

See the code below and the algorithm explanation on the figure.

Explanation:

The explanation in order to get the answer is given on the figure below.

Solving this problem with C. The program is given below:

#include <stdio.h>

int main(void) {

   int n, Even=0, Odd=0, Zeros=0;  

   for (;;) {

       printf("\nEnter the value the value that you want to check(remember just integers): ");

       //IF we input a non-numeric character the code end;

       if (scanf("%d", &n) != 1) break;

       if (n == 0) {

           Zeros++;

       }

       else {

           if (n % 2) {

               Even++;

           }

           else {

               Odd++;

           }

       }

   }  

   printf("for this case we have %d even, %d odd, and %d zero values.", Even, Odd, Zeros);

   return 0;

}

5 0
3 years ago
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