Answer:
Volume = 125 mm^3
Step-by-step explanation:
Here, we want to get the volume of the cube
What we have to do here is to substitute the value of the area
We have this as
:
V = 25^(3/2)
V = (√25)^3
V = 5 * 5 * 5 = 125 mm^3
You have the answer if you just do a little bit more but other than that you have your answer
Answer:
83%
Step-by-step explanation:
We can put this into a fraction to get the ratio of the new price over the old price
This will give us the percentage of how much was decreased.
The answer you get is .83
Bring 2 decimal places to the right to get 83 (converting from decimal to percentage)
You get 83 percent to be your answer
We can see on this graph that the triangle has legs of x and 6 with a hypotenuse of 10 and we can use Pythagoreans theorem to find the unknown side.
Pythagoreans theorem: a^2+b^2=c^2, where a and b are the legs of the triangle and c, is the hypotenuse
x^2+6^2=10^2 Plugin a=x, b=6, and c=10. Now let us solve for x
x^2+36=100 Square each individual term
x^2+=100+36 Subtract 36 from both sides
x^2=64 Combine like terms
sqrt(2)=sqrt(64) Take the square root of both sides
x = 8 Simplify the square root
So our answer is x = 8
The ladder touches the 8 feet mark on the wall.
Let h represent the height of the trapezoid, the perpendicular distance between AB and DC. Then the area of the trapezoid is
Area = (1/2)(AB + DC)·h
We are given a relationship between AB and DC, so we can write
Area = (1/2)(AB + AB/4)·h = (5/8)AB·h
The given dimensions let us determine the area of ∆BCE to be
Area ∆BCE = (1/2)(5 cm)(12 cm) = 30 cm²
The total area of the trapezoid is also the sum of the areas ...
Area = Area ∆BCE + Area ∆ABE + Area ∆DCE
Since AE = 1/3(AD), the perpendicular distance from E to AB will be h/3. The areas of the two smaller triangles can be computed as
Area ∆ABE = (1/2)(AB)·h/3 = (1/6)AB·h
Area ∆DCE = (1/2)(DC)·(2/3)h = (1/2)(AB/4)·(2/3)h = (1/12)AB·h
Putting all of the above into the equation for the total area of the trapezoid, we have
Area = (5/8)AB·h = 30 cm² + (1/6)AB·h + (1/12)AB·h
(5/8 -1/6 -1/12)AB·h = 30 cm²
AB·h = (30 cm²)/(3/8) = 80 cm²
Then the area of the trapezoid is
Area = (5/8)AB·h = (5/8)·80 cm² = 50 cm²
