Answer:
Probability of drawing non defective bulb
=90/100×89/99×88/98×...........×82/92..........(i)=90/100×89/99×88/98×...........×82/92..........(i)
Now the probability of drawing at least one bulb will be defective
=1−(i)=1−90/100×89/99×88/98×...........×82/92
1−(90/100⋅89/99⋅…⋅83/93)
Answer:
(-1, -5)
Step-by-step explanation:

1. We must calculate x, for that we must substitute y, so we have:
5x=9x+4
2. Now we solve the equation.
5x-9x=4
-4x=4
x=-1
3. Now we must calculate y
y=5x
y=5(-1)
y=-5
And the answer is (-1, -5)
Lets say you have a spinner with 6 sides. Numbers 1-6
The probability of each number to be landed on is 1/6 or about 16%
For an even number to be landed on, it would be 3/6 or 1/2 or 50% bc there are 3 even numbers: 2,4, and 6
The median is 82
The mode is 73
The mean is 80.8
√180 = √(2 x 2 x 3 x 3 x 5) = 6√5