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3 years ago

Factor polynomial -3x^2-16x-5

Mathematics

1 answer:

forsale [732]3 years ago

8 0

Answer:

-(3x^2 + 16x + 5)

-(3x+1)(x+5)

Step-by-step explanation:

-1(3x^2+15x+x+5)

-1(3x^2+16x+5)

-3x^2-16x-5

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Verify if f(x)= 5-3x/2 and g(x)= 5-2x/3 are inverses. Please show step by step.

mestny [16]

Since f(g(x)) = g(f(x)) = x, hence the function f(x) and g(x) are inverses of each other.

<h3>Inverse of functions</h3>

In order to determine if the function f(x) and g(x) are inverses of each other, the composite function f(g(x)) = g(f(x))

Given the function

f(x)= 5-3x/2 and

g(x)= 5-2x/3

f(g(x)) = f(5-2x/3)

Substitute

f(g(x)) = 5-3(5-2x)/3)/2

f(g(x)) = (5-5+2x)/2

f(g(x)) = 2x/2

f(g(x)) = x

Similarly

g(f(x)) = 5-2(5-3x/2)/3

g(f(x)) = 5-5+3x/3

g(f(x)) = 3x/3

g(f(x)) =x

Since f(g(x)) = g(f(x)) = x, hence the function f(x) and g(x) are inverses of each other.

Learn more on inverse of a function here: brainly.com/question/19859934

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7 0

1 year ago

X-y=2<br>x² -7y² = 2<br>decide the system

olya-2409 [2.1K]

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3 years ago

A design engineer wants to construct a sample mean chart for controlling the service life of a halogen headlamp his company prod

tekilochka [14]

Answer:

C) 515 hours.

D) 500 hours

c) sample 3

Step-by-step explanation:

1. Sample 2 mean = x2`= ∑x2/n2= 2060/4= 515 hours

Sample Service Life (hours)

1 2 3

495 525 470

500 515 480

505 505 460

x1`= ∑x1/n1= 2000/4= 500 hours

x2`= ∑x2/n2= 2060/4= 515 hours

x3`= ∑x3/n3= 1880/4= 470 hours

2. The mean of the sampling distribution of sample means for whenever service life is in control is 500 hours . It is the given mean in the question and the limits are determined by using μ ± σ , μ±2 σ or μ ± 3 σ.

In this question the limits are determined by using μ ± σ .

3. Upper control limit = UCL = 520 hours

Lower Control Limit= LCL = 480 Hours

Sample 1 mean = x1`= ∑x1/n1= 2000/4= 500 hours

Sample 2 mean = x2`= ∑x2/n2= 2060/4= 515 hours

Sample 3 mean = x3`= ∑x3/n3= 1880/4= 470 hours

This means that the sample mean must lie within the range 480-520 hours but sample 3 has a mean of 470 which is out of the given limit.

We see that the sample 3 mean is lower than the LCL. The other two means are within the given UCL and LCL.

This can be shown by the diagram.

8 0

2 years ago

Put a digit in the gap, such that the answer is a whole number:

Makovka662 [10]

Answer: The possible digits are 2,5 and 8

Step-by-step explanation:

3x +486 = 100_

From the equation in the question, we are looking for a digit to put in the gap after 100 to make sure that when we solve the question, x will be a whole number.

Therefore, since it's a single digit required, the possible digits will be from 0 to 9.

Now, from divisibilty tests, for a number from 2 digits upwards to be divisible by 3, the sum of its digits has to be divisible by 3.

Going back to the question, let's divide each term by 3 to get ;

3x/3 + 486/3 = 100_ to give ;

x + 162 = 100_ /3

Now for x to be a whole number, the value on the right hand side must be a whole number.

Therefore, since we know that for a 2 digits and above number to be divisible by 3,it's sum must be divisible by 3. We can plug in any of the digits from 0-9 into the gap and add up.

For 0; 1+0+0+0= 1

For 1; 1+0+0+1 = 2

For 2; 1+0+0+2= 3

Following the same addition pattern for digits 3,4,5,6,7,8and 9, we'll get sum of 4,5,6,7,8,9 and 10 respectively.

Inspecting the above, the only additions that are divisible by 3 are when the digit is; 2,5 and 8

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3 years ago

How many cenimeters are 1 meter

aleksley [76]

100 cm

1 m is equivalent to 100cm

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3 years ago

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