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1 answer:
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the real solutions for the equation are -
Step-by-step explanation:
=
= 0
We can write 64 as
+
= 0
using the identity ( )
we get,
=
= ....................(1)
solving the quadratic equation ,
=0
solutions of this quadratic equation can be obtained by
let use y for factors
<u /> ..................(2)
from the equation 1 we have,
which gives solution
and from equation 2 we got
so the real solutions for the equation are -
Option A: z + 1
Option B: 6 + w
Option D:
Solution:
Let us first define the polynomial.
A polynomial can have constants, variables, exponents and fractional coefficients.
A polynomial cannot have negative exponents, fractional exponents and never divided by a variable.
<u>To find which expressions are polynomial:</u>
Option A: z + 1
By the definition, z + 1 is a polynomial.
It is polynomial.
Option B: 6 + w
By the definition, 6 + w is a polynomial.
It is polynomial.
Option C:
Here, y have fractional exponent.
So, it is not a polynomial.
Option D:
By the definition, is a polynomial.
It is polynomial.
Hence z + 1, 6 +w and are polynomials.
Look at the graph, which y values can the graph hit?
Anything above zero would be the right answer, since there is an asymptote at .
So the range would be
Hope this helps.
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