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Montano1993 [528]
3 years ago
8

Can someone help me out?

Mathematics
2 answers:
LiRa [457]3 years ago
7 0

1. perimeter = 4 and area = 1

2. permeter = 8 and area = 4

3. perimeter = 12 and area = 9

4. perimeter = 16 and area = 16

5. perimeter = 20 and area = 25

Irina18 [472]3 years ago
3 0

Answer:

length of side: 1, 2,3,4,5

perimiter: 4,8,12,16,20

area: 1, 4, 9, 16, 25

Step-by-step explanation:

for perimiter add all sides, for area multiply hight and width

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Convert x2 + y2 -4x = 0 to polar form.
Bingel [31]

Answer:

r(r-4\cos \theta)=0

Step-by-step explanation:

We are given the following equation:

x^2 + y^2 -4x = 0

We have to convert it into polar form.

We put

x = r \cos \theta\\y = r\sin \theta

Putting values, we get:

x^2 + y^2 -4x = 0\\(r\cos \theta)^2 + (r\sin \theta)^2 - 4(r\cos \theta) = 0\\r^2(\cos^2 \theta + \sin^2 \theta) - 4r\cos \theta = 0\\r^2 - 4r\cos \theta = 0\\r(r-4\cos \theta)=0

is the required polar form.

7 0
3 years ago
Will mark brainliest
emmasim [6.3K]
Since line t is a transversal line all angle which are perpendicular with 63 will equal to the same value (63) and also line m is a straight line where it’s total will be 180

So,
3x + 2x + 63 = 180
5x + 63 = 180
5x = 180 - 63
5x = 117
Divide by 5 throughout
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4 0
2 years ago
Read 2 more answers
Obtain the general solution to the equation. (x^2+10) + xy = 4x=0 The general solution is y(x) = ignoring lost solutions, if any
alukav5142 [94]

Answer:

y(x)=4+\frac{C}{\sqrt{x^2+10}}

Step-by-step explanation:

We are given that a differential equation

(x^2+10)y'+xy-4x=0

We have to find the general solution of given differential equation

y'+\frac{x}{x^2+10}y-\frac{4x}{x^2+10}=0

y'+\frac{x}{x^2+10}y=4\frac{x}{x^2+10}

Compare with

y'+P(x) y=Q(x)

We get

P(x)=\frac{x}{x^2+10}

Q(x)=\frac{4x}{x^2+10}

I.F=e^{\int\frac{x}{x^2+10} dx}=e^{\frac{1}{2}ln(x^2+10)}

e^{ln\sqrt(x^2+10)}=\sqrt{x^2+10}

y\cdot \sqrt{x^2+10}=\int \frac{4x}{x^2+10}\times \sqrt{x^2+10} dx+C

y\cdot \sqrt{x^2+10}=\int \frac{4x}{\sqrt{x^2+10}}+C

y\cdot \sqrt{x^2+10}=4\sqrt{x^2+10}+C

y(x)=4+\frac{C}{\sqrt{x^2+10}}

6 0
3 years ago
Anna is in a cave 50 feet below the cave entrance. She descends 12 feet, then ascends 15 feet. Find her new position relative to
Mademuasel [1]

Answer:

53

Step-by-step explanation:

50 - 12 = 38

38 + 15 = 53

7 0
3 years ago
using the following image. findUsing the attached image, apply what you have lease about linear pairs and solve for x.
natka813 [3]

Answer:

Step-by-step explanation:

Linear pairs

(4x + 1)  + 75  = 180

Add the like terms

4x +  76 = 180

Subtract 76 from both sides,

4x = 180- 76

4x = 104

Divide both sides by 4

x = 104/4

x = 26

5 0
3 years ago
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