Answer:
I think this ans may help you
Answer:
1919=0+1+0+1=2
Step-by-step explanation:
Answer:
Option C 5/12 is correct option
Step-by-step explanation:
We have to find the probability that shows yellow dice has a larger value than the red dice.
Probability= total no of favorable outcomes / total no of outcomes
in our case, considering the data set, we have to find those pair where value of yellow die is greater than the red die. Where (1,2) represents 1 on the red die and 2 on the yellow die
(1,2) (1,3) (1,4) (1,5) (1,6)
(2,3) (2,4) (2,5) (2,6)
(3,4) (3,5) (3,6)
(4,5) (4,6)
(5,6)
These are the possibilities where yellow die has greater value than red die.
total no of favorable outcomes = 15
total no of outcomes = 36
probability that yellow die has greater value than red die = 15 / 36
= 5/ 12
Option C 5/12 is correct option
Let
x ----------> the height of the whole poster
<span>y ----------> the </span>width<span> of the whole poster
</span>
We need
to minimize the area A=x*y
we know that
(x-4)*(y-2)=722
(y-2)=722/(x-4)
(y)=[722/(x-4)]+2
so
A(x)=x*y--------->A(x)=x*{[722/(x-4)]+2}
Need to minimize this function over x > 4
find the derivative------> A1 (x)
A1(x)=2*[8x²-8x-1428]/[(x-4)²]
for A1(x)=0
8x²-8x-1428=0
using a graph tool
gives x=13.87 in
(y)=[722/(x-4)]+2
y=[2x+714]/[x-4]-----> y=[2*13.87+714]/[13.87-4]-----> y=75.15 in
the answer is
<span>the dimensions of the poster will be
</span>the height of the whole poster is 13.87 in
the width of the whole poster is 75.15 in
