Answer: at the values where cos(x) = 0Justification:1) tan(x) = sin(x) / cos(x).
2) functions have vertical asymptotes at x = a if Limit of the function x approaches a is + or - infinity.
3) the limit of tan(x) approaches +/- infinity where cos(x) approaches 0.
Therefore, the grpah of y = tan(x) has asymptotes where cos(x) = 0.
You can see the asympotes at x = +/- π/2 on the attached graph. Remember that cos(x) approaches 0 when x approaches +/- (n+1) π/2, for any n ∈ N, so there are infinite asymptotes.
Answer:
vertex: (-1,25)
aos; -1
left x int: -6
right x int: 4
(not sure)
range is less than of equal to 25
Answer:
330
Step-by-step explanation:
6x²+4x+8
Let x=7
6 ( 7)^2 + 4(7) +8
6*49+ 28+8
294+28+8
330