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3 years ago

15

Integral

-%202x%20-%208%20" id="TexFormula1" title="x^{3} - 7x^{2} + 5x + 40 \div x^{2} - 2x - 8 " alt="x^{3} - 7x^{2} + 5x + 40 \div x^{2} - 2x - 8 " align="absmiddle" class="latex-formula">

1 answer:

solong [7]3 years ago

6 0

Answer:

$ext^{4}-7x^{2}+3x+401dvx^{2}i-8ext$

Step-by-step explanation:

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3 years ago

What is the value of this expression when a = 2 and b = -3 ? a^3 - b^3 / 5

saveliy_v [14]

Answer:

13 2/5

Step-by-step explanation:

a = 2 and b = -3

so the question asks whats.... a^3 - b^3/5

First we plug in the values of a and b

(2)^3 - (-3)^3 /5

Now we solve the ones in paranthesis first

(2)^3 = 8 because 2×2×2 and

-(-3)^3 forget about the - outside the parenthesis so

(-3)^3 = (-27) because (-3)×(-3)×(-3)

now we put it back together

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the two minus become plus so

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Now we solve it like fractions

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simplify

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Hope that helps!

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3 years ago

Solve the equation by Completing the Square<br> x2 – 10x + 13 = 0

user100 [1]

Answer:

$x=5+\sqrt{12}$

or

$x=5-\sqrt{12}$

Step-by-step explanation:

$x^2-10x+13=0$

$x^2-10x=-13$

$x^2-10x+(\frac{10}{2})^2 =-13+(\frac{10}{2})^2$

$x^2-10x+(5)^2=-13+(5)^2$

$x^2-10x+25=-13+25\\x^2-10x+25=12$

Factor.

$(x-5)^2=12$

Extract the square root.

$x-5=\frac{+}{} \sqrt{12}$

Add 5

$x=5+\sqrt{12}$

or

$x=5-\sqrt{12}$

4 0

3 years ago

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