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vagabundo [1.1K]
2 years ago
9

What are the values of AB and DE in parallelogram ABCD? AB=? PLEASE HELP

Mathematics
1 answer:
GarryVolchara [31]2 years ago
5 0

Answer:

AB=12

ED=6

Step-by-step explanation:

AB=CD=12

BC=AD=26

ED=26-20=6

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Which of the following is a congruence transformation?
Gennadij [26K]
The answer is C. Reflecting
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3 years ago
Suppose that θ is an acute angle of a right triangle and that sec(θ)=52. Find cos(θ) and csc(θ).
insens350 [35]

Answer:

\cos{\theta} = \dfrac{1}{52}

\csc{\theta} = \dfrac{52}{\sqrt{2703}}

Step-by-step explanation:

To solve this question we're going to use trigonometric identities and good ol' Pythagoras theorem.

a) Firstly, sec(θ)=52. we're gonna convert this to cos(θ) using:

\sec{\theta} = \dfrac{1}{\cos{\theta}}

we can substitute the value of sec(θ) in this equation:

52 = \dfrac{1}{\cos{\theta}}

and solve for for cos(θ)

\cos{\theta} = \dfrac{1}{52}

side note: just to confirm we can find the value of θ and verify that is indeed an acute angle by \theta = \arccos{\left(\dfrac{1}{52}\right)} = 88.8^\circ

b) since right triangle is mentioned in the question. We can use:

\cos{\theta} = \dfrac{\text{adj}}{\text{hyp}}

we know the value of cos(θ)=1\52. and by comparing the two. we can say that:

  • length of the adjacent side = 1
  • length of the hypotenuse = 52

we can find the third side using the Pythagoras theorem.

(\text{hyp})^2=(\text{adj})^2+(\text{opp})^2

(52)^2=(1)^2+(\text{opp})^2

\text{opp}=\sqrt{(52)^2-1}

\text{opp}=\sqrt{2703}

  • length of the opposite side = √(2703) ≈ 51.9904

we can find the sin(θ) using this side:

\sin{\theta} = \dfrac{\text{opp}}{\text{hyp}}

\sin{\theta} = \dfrac{\sqrt{2703}}{52}}

and since \csc{\theta} = \dfrac{1}{\sin{\theta}}

\csc{\theta} = \dfrac{52}{\sqrt{2703}}

4 0
3 years ago
-3(5)^2-(-2)(-8) simplify
avanturin [10]

To do this, we're going to use the order of operations (PEMDAS):

P - Parentheses

E - Exponents

M - Multiplication

D - Division

A - Addition

S - Subtraction

First let's do parentheses, there isn't anythig in parentheses we need to simplify, so we can skip this step.

Next let's look for exponents. I see we have a 5^2 so let's replace that with 5^2=25:

-3(25)-(-2)(-8)

Now let's look for multiplcation. We know that things that are right next to eachother in parentheses represent multiplcation, so let's simply this more:

-3(25)=-75

(-2)(-8)=16

-75-16

And now we're left with a simple problem we know how to solve.

Answer: -91

Hope this helps!

3 0
3 years ago
PLZ HELP SCALE FACTOR TRIANGLE<br><br> A. 10.5 cm<br> B. 31.5 cm<br> C. 63 cm<br> D. 189 cm
Anarel [89]

If two similar triangles have sides in the ratio a : b, then their areas are in the ratio a² : b².

We have the ratio:

54:18=\dfrac{54}{18}=3:1

Area of the smaler triangle = x

Area of the larger triangle = 567 cm²

Therefore we have the equation:

567:x=3^2:1^2\\\\\dfrac{567}{x}=\dfrac{9}{1}\qquad|\text{cross multiply}\\\\9x=567\qquad|\text{divide both sides by 9}\\\\x=63

<h3>Answer: C. 63 cm²</h3>
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3 years ago
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julia-pushkina [17]

You need to have variables one one side and constants on the other.  ax - ax + by = c - ax by = c - ax by/b = (c - ax)/b y = (c - ax)/b

8 0
3 years ago
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