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konstantin123 [22]

4 years ago

6

Carey has 30 CDs and wants to take pick out 5 to put into her CD player. How many different combinations of CDs can she pick out

?
C(30, 5)
C(25, 5)
30!

2 answers:

11111nata11111 [884]4 years ago

7 0

Answer:

A. C(30, 5)

Step-by-step explanation:

We have been given that Carey has 30 CDs and wants to take pick out 5 to put into her CD player. We are asked to find the number of different combinations of CDs can she pick out.

We will use combinations to solve our given problem.

$_{r}^{n}\textrm{C}=\frac{n!}{r!(n-r)!}$ , where,

$n=\text{Total number of items}$ ,

$r=\text{Number of items being chosen at a time}$

Upon substituting our given values in above formula we will get,

$_{5}^{30}\textrm{C}=\frac{30!}{5!(30-5)!}$

$_{5}^{30}\textrm{C}=\frac{30!}{5!(25)!}$

$_{5}^{30}\textrm{C}=\frac{30*29*28*27*26*25!}{5*4*3*2*1*25!}$

$_{5}^{30}\textrm{C}=29*7*27*26$

$_{5}^{30}\textrm{C}=142506$

Therefore, Carey can pick 5 CDs from 30 CDs in $_{5}^{30}\textrm{C}=142506$ ways and option A is the correct choice.

Solnce55 [7]4 years ago

3 0

The correct answer is C(30,5)
<span>
That's because you have to know factorials and apply the formulas to find out that:
30! / [5!(30 - 5!)]
30! / (5! * 25!), which means that there are </span>142506 combinations, or C(30,5)

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3 years ago

An engineer has designed a valve that will regulate water pressure on an automobile engine. The valve was tested on 100100 engin

Margaret [11]

Answer:

Null hypothesis: $\mu \geq 7.3$

Alternative hypothesis: $\mu < 7.3$

$z=\frac{7.2-7.3}{\frac{0.81}{\sqrt{100}}}=-1.235$

$p_v =P(z$

If we compare the p value and the significance level given $\alpha=0.01$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, so then we can conclude that the mean pressure for the automobile engines is not significantly less than 7.3 at 1% of significance.

Step-by-step explanation:

1) Data given and notation

$\bar X=7.2$ represent the sample mean

$\sigma=0.81$ represent the population standard deviation

$n=100$ sample size

$\mu_o =7.3$ represent the value that we want to test

$\alpha=0.01$ represent the significance level for the hypothesis test.

z would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

2) State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean pressure is lower than the specificated value 7.3, the system of hypothesis are :

Null hypothesis: $\mu \geq 7.3$

Alternative hypothesis: $\mu < 7.3$

Since we know the population deviation, is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:

$z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}$ (1)

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

3) Calculate the statistic

We can replace in formula (1) the info given like this:

$z=\frac{7.2-7.3}{\frac{0.81}{\sqrt{100}}}=-1.235$

4) P-value

Since is a one-side lower test the p value would given by:

$p_v =P(z$

5) Conclusion

If we compare the p value and the significance level given $\alpha=0.01$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, so we can conclude that the mean pressure for the automobile engines is not significantly less than 7.3 at 1% of significance.

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Step-by-step explanation:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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