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konstantin123 [22]
3 years ago
6

Carey has 30 CDs and wants to take pick out 5 to put into her CD player. How many different combinations of CDs can she pick out

?
C(30, 5)
C(25, 5)
30!
Mathematics
2 answers:
11111nata11111 [884]3 years ago
7 0

Answer:

A. C(30, 5)

Step-by-step explanation:

We have been given that Carey has 30 CDs and wants to take pick out 5 to put into her CD player. We are asked to find the number of different combinations of CDs can she pick out.

We will use combinations to solve our given problem.

_{r}^{n}\textrm{C}=\frac{n!}{r!(n-r)!}, where,

n=\text{Total number of items},

r=\text{Number of items being chosen at a time}

Upon substituting our given values in above formula we will get,

_{5}^{30}\textrm{C}=\frac{30!}{5!(30-5)!}

_{5}^{30}\textrm{C}=\frac{30!}{5!(25)!}

_{5}^{30}\textrm{C}=\frac{30*29*28*27*26*25!}{5*4*3*2*1*25!}

_{5}^{30}\textrm{C}=29*7*27*26

_{5}^{30}\textrm{C}=142506

Therefore, Carey can pick 5 CDs from 30 CDs in _{5}^{30}\textrm{C}=142506 ways and option A is the correct choice.

Solnce55 [7]3 years ago
3 0
The correct answer is C(30,5)
<span>
That's because you have to know factorials and apply the formulas to find out that:
30! / [5!(30 - 5!)]
30! / (5! * 25!), which means that there are </span>142506 combinations, or C(30,5)


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