The present age of Annillee, which is two-thirds of Jessie's present age, is <u>30 years</u>, while Jessie's is <u>45 years</u>.
<h3>How are the ages determined?</h3>
Their present ages can be determined using a system of equations as below.
<h3>Data and Calculations:</h3>
Let the present age of Annilee = ²/₃y
Let the present of Jessie = y
Ages of Annilee and Jessie in 14 years:
Annilee's age = ²/₃y + 14
Jessie's age = y + 14
Sum of their ages in 14 years = ²/₃y + 14 + y + 14
= 103
²/₃y + 14 + y + 14 = 103
²/₃y + y = 75
1²/₃y = 75
y = 75/1²/₃
y = 75/5 x 3
y = 45
<h3>Present Ages:</h3>
Annilee = ²/₃y = ²/₃ x 45 = 30 years
Jessie = y = 45
<u>Check</u>:
²/₃ x 45 + 14 = 44
45 + 14 = 59
Sum of ages in 14 years = 103 (59 + 44) or (30 + 14 + 45 + 14)
Thus, at present, Annilee's age is <u>30 years</u>, while Jessie is <u>45 years</u>.
Learn more about equations at brainly.com/question/2972832
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