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Scrat [10]
3 years ago
15

17. When a single set of values is randomly divided into two equal groups, explain how the means of these two groups may be very

different from each other and may be very different
from the mean of the single set of values.
Mathematics
1 answer:
joja [24]3 years ago
7 0

If you take 2 groups of equal cardinality, it could happen that, for example, many of the higher values go to the first group and therefore, many of the low values go to the second group, making their respective means quite different and different from the original sample mean. This could even go worse due to the possible existence of outliers, that is, values that are far different than the sample mean. An outlier tend to disrup the mean of a sample, but for smaller samples the result is much dramatic.

For example, let X be {1,2,3,4,5,6,7,8,9,100}

The elements of X sum 145, hence the mean of X is 14,5. Let divide X in two groups

Y = {1,2,3,5,9}

Z = {4,6,7,8,100}

The elements of Y sum 20, so its mean is 4

The elements of Z sum 125, so its mean is 25

Both means are quite different from each other and quite different from the mean of X. Note that if we take the mean of the means the result is 4+25/2 = 14,5 which is equal to the mean of X.

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What is the area of a rectangle that is 2 meters long and 12 meters wide?
patriot [66]

Answer:

24m²

Step-by-step explanation:

To find the area of a rectangle, we use the formula A = l * w or Area = length * width.

We know that our length is 2 meters and our width is 12 meters so we can plug these values into the formula to get our answer.

A = 2 * 12 = 24

Remember that area is measured in "square" units and must be raised to the 2nd power.

A = 24m²

3 0
3 years ago
A school principal plans to form teams from 126 third-graders, 180 fourth-graders, and 198 fifth-graders so that there is the sa
marissa [1.9K]

Answer:

There are 9 teams possible each having 14 third-graders, 20 Fourth-graders, 22 Fifth-graders

Step-by-step explanation:

126 third-graders

180 fourth-graders

198 fifth-graders

Find the highest common factor of 126, 180, 198

Factors of 126: 1, 2, 3, 6, 7, 9, 14, 18, 21, 42, 63, 126.

Factors of 180 : 1, 2, 3, 4, 5, 6, 9, 10, 12, 15, 18, 20, 30, 36, 45, 60, 90, 180

Factors of 198: 1, 2, 3, 6, 9, 11, 18, 22, 33, 66, 99, 198.

The highest common factor of 126, 180, 198 is 9

The largest possible number of teams that can be formed is 9

Each team has

third-graders = 126 / 9

= 14

Fourth-graders = 180 / 9

= 20

Fifth-graders = 198 divided by 9

= 22

There are 9 teams possible each having 14 third-graders, 20 Fourth-graders, 22 Fifth-graders

3 0
3 years ago
The 6 boys in Ms.dreyvus’ class always ran together during recess.
mr_godi [17]

Answer:

36 miles each

Step-by-step explanation:

you divide 192 by 6 = 36

hope this helps

Mark brainliest please

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50-35.65
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3 years ago
Graph f(x)=1.99x+3 HURRY 27 BRAINLY POINTS
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Answer:

0, 3

Step-by-step explanation:

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2 years ago
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